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crimeas [40]
3 years ago
8

With an average acceleration of 1.5 m/s2, how long will it take a driver to accelerate from

Physics
1 answer:
Ratling [72]3 years ago
6 0

Answer:

Below

Explanation:

You can use this formula to find the time it will take the driver :

      finalvelocity = initialvelocity + acceleration (time)

Just plug in the values and rearrange :

     6.94 m/s = 0 m/s + 1.5m/s^2 (t)

     6.94 m/s = 1.5m/s^2 t

     4.6366 s = t

Therefore it takes the driver 4.6 seconds to accelerate to 25 km/h

Hope this helps! Best of luck <3

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What unita are used to measure electrical current​
JulijaS [17]

Answer:

It's called an ampere!

Explanation:

The SI unit of electric current is the ampere, which is the flow of electric charge across a surface at the rate of one coulomb per second. The ampere (symbol: A) is an SI base unit Electric current is measured using a device called an ammeter.

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3 years ago
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A high ____will have a short wavelength.​
Sphinxa [80]

Question:

A high ____will have a short wavelength

Answer:

That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths

Explanation:

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A bicycle is a compound machine, true or false
JulsSmile [24]

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3 years ago
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Each year, an average person in the United States is exposed to a radiation level of _____.
Anna11 [10]

Answer:

The correct answer is 0,2 rems

Explanation:

People are exposed to natural sources of radiation all the time. According to recent estimates, the average person in the United States receives an effective dose of approximately 3 mSv per year of natural radiation, which is equivalent to 0.3 rems. This amount includes cosmic radiation from outer space and is average because it varies depending on the region people are in.

The amount of radiation for a chest x-ray of an adult (0.01 rems) is approximately equal to 10 days of natural radiation to which we are all exposed every day.

Have a nice day!

3 0
3 years ago
determine the pressure exerted on the surface of a submarine cruising 175 ft below the free surface of the sea. assume that the
Alenkasestr [34]

Answer:

92.81 psia.

Explanation:

The density of water by multiplying its specific gravity by the density of sea water.

SG = density of sea water/density of water

ρ = SG x ρw

1 kg/m3 = 62.4 lbm/ft^3

= 1.03 * 62.4

= 64.27lbm/ft^3.

The absolute pressure at 175 ft below sea level as this is the location of the submarine.

P = Patm +ρgh

= 14.7 + 64.27 * 32.2 * 175

Converting to pound force square inch,

= 14.7 + 64.27 * (32.2ft/s^2) * (175ft) * (1lbf/32.2lbm⋅ft/s^2) * (1ft^2/144in^2 )

= 14.7 + 78.11 psia

= 92.81 psia.

8 0
3 years ago
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