Answer:
1.137278672 m/s
+5.9 cm or -5.9 cm
Explanation:
A = Amplitude = 6.25 cm
m = Mass of object = 225 g
k = Spring constant = 74.5 N/m
Maximum speed is given by
The maximum speed of the object is 1.137278672 m/s
Velocity is at any instant is given by
The locations are +5.9 cm or -5.9 cm
Answer:
The pack has fallen 275.6 m
Explanation:
The pack is in free fall, so it is moving by uniform accelerated motion, so we can use the following suvat equation:
where, choosing upward as positive direction:
v is the final velocity
u is the initial velocity
is the acceleration of gravity
s is the vertical displacement
For the pack in this problem,
u = 0
v = -73.5 m/s
Solving for s, we find how far the packet has fallen:
And the negative sign means the direction of the displacement is downward.
Answer:
h = v₀ g / a
Explanation:
We can solve this problem using the kinematic equations. As they indicate that the air does not influence the vertical movement, we can find the time it takes for the body to reach the floor
y = t - ½ g t²
The vertical start speed is zero
t² = 2t / g
The horizontal document has an acceleration, with direction opposite to the speed therefore it is negative, the expression is
x = v₀ₓ t - ½ a t²
Indicates that it reaches the same exit point x = 0
v₀ₓ t = ½ a t2
v₀ₓ = ½ a (2h / g)
v₀ₓ = v₀
h = v₀ g / a