1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vredina [299]
3 years ago
13

1. A pipeline constructed of carbon steel failed after 3 years of operation. On examination it was found that the wall thickness

had been reduced by corrosion to about half the original value. The pipeline was constructed of nominal 100 mm (4 in) schedule 40 pipe, inside diameter 102.3 mm (4.026 in), outside diameter 114.3 mm (4.5 in). Estimate the rate of corrosion in ipy and mm per year.
2. The pipeline described in question 1 above was used to carry wastewater to a hold-up tank. The effluent is not hazardous. A decision has to be made on what material to use to replace the pipe. Three suggestions have been made: a. Replace with the same schedule carbon steel pipe and accept renewal at 3-year intervals. b. Replace with a thicker pipe, schedule 80, outside diameter 114.3 mm (4.5 in), inside diameter 97.2 mm (3.826 in). c. Use stainless steel pipe, which will not corrode.

The estimated cost of the pipes, per unit length is: schedule 40 carbon steel $5, schedule 80 carbon steel $8.30, stainless steel (304) schedule 40 $24.80. Installation and fittings for all the materials adds $16.5 per unit length. The downtime required to replace the pipe does not result in a loss of production. If the expected future life of the plant is 7 years, recommend which pipe to use.
Engineering
1 answer:
jek_recluse [69]3 years ago
3 0

Answer:

check the explanation

Explanation:

1.

Thickness Loss = t =\frac{t_{o}-t_{i}}{2} = \frac{114.3-102.3}{2} = 2mm

t_{f} = \frac{1}{2}*6 = 3mm

Hence Rate of Corrosion = 6*\frac{1-0.5}{3} = 1mm/year = 0.03 inches per year

2.

As the expected future life is 7 years,

40 carbon steel pipe has to be replaced every 3 years as given in the question,

Cost per unit length is the sum of material cost and installation cost.

Cost of 40 carbon steel = (5 dollars + 16.5 dollars) * 3 = 64.5 dollars

For 80 carbon steel pipe, first calculate the thickness loss,

\frac{114.3-97.2}{2} = 8.55mm

The critical thickness is given to be 3mm, Hence change in thickness is 8.55-3 = 5.5mm

This 80 carbon steel pipe has to be replaced one more time

Hence, Cost per unit length is the sum of material cost and installation cost.

Cost of 80 carbon steel = (8.3 dollars + 16.5 dollars) * 2 = 49.6 dollars

The best is of stainless steel which does not undergo corrosion at all and thus it needs to be replaced only once throughout the plant operation. Its cost = 24.8 dollars + 16.5 dollars = 41.3 dollars

Hence, stainless steel is the recommended pipe to be used.

You might be interested in
explain each of the following kinds of rockets: Solid-Fuel Rocket, Liquid-Fuel Rocket, Ion Rocket and Plasma Rocket.
Rudik [331]

Answer:

ur answer friend

Explanation:

answer

<em>S</em><em>o</em><em>l</em><em>i</em><em>d</em><em>-</em><em>F</em><em>u</em><em>e</em><em>l</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>a solid-propellant rocket or solid rocket is a rocket with a rocket engine that uses solid propellants. The earliest rockets were solid-fuel rockets powered by gunpowder; they were used in warfare by the Chinese, Indians, Mongols and Persians, as early as 13th century.

<em>L</em><em>i</em><em>q</em><em>u</em><em>i</em><em>d</em><em>-</em><em>F</em><em>u</em><em>e</em><em>l</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>a liquid-propellant rocket or liquid rocket utilizes a rocket engine that use liqiud propellants. An inert gas stored in a tank at a high pressure is sometimes used instead of pumps in simpler small engines to force the propellants into the combustion chamber.

<em>I</em><em>o</em><em>n</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>an ion thruster or ion drive is a form of electric propulsion used for spacecraft propulsion. It creates thrust by accelerating ions using electricity. The Deep Space 1 spacecraft, powered by an ion thruster, changed velocity by 4.3 km/s ( 9600 mph ) while consuming less than 74 kg ( 163 lb ) of xenon.

<em>P</em><em>l</em><em>a</em><em>s</em><em>m</em><em>a</em><em> </em><em>R</em><em>o</em><em>c</em><em>k</em><em>e</em><em>t</em><em> </em><em>-</em><em> </em>in this type of rocket, a combination of electric and magnetic fields are used to break down the atoms and molecules of a propellant gas into a collection of particles that have either a positive charge (ions) or a negative charge (electrons). In other words, the propellant gas becomes a plasma.

I think its helpful to you

Please mark as brainliest answer

5 0
3 years ago
Tech A says that bleeding an electronic brake control system is just like bleeding a non-electronic brake control system. Tech B
PtichkaEL [24]

Answer:

Tech A is correct.

Explanation:

An electric brake controller is a device that sends a signal to the trailer via vehicle's brakes. This reduces the wear and tear on the vehicle brakes. As a result, the vehicle stops.

Tech A says that bleeding an electronic brake control system is just like bleeding a non-electronic brake control system.

So,

Tech A is correct.

3 0
3 years ago
What is a table saw for
svet-max [94.6K]

Answer:

a table

Explanation:

because you can saw the table

5 0
2 years ago
Read 2 more answers
Obtain a relation for the logarithmic mean temperature difference for use in the LMTD method?
kolezko [41]

Answer:

The log mean temperature difference is:

ΔT,lm=(ΔT1-ΔT2)/㏑(ΔT1/ΔT2)

Explanation:

To evaluate the equivalent average temperature difference between two fluids we consider a parallel-flow double-pipe heat exchanger (see attached diagram). The temperature of the hot and cold fluids is large at the inlet of the heat exchanger and decreases exponentially toward the outlet.  

We can assume that the outer surface of the heat exchanger is well insulated and that heat transfer only occurs between the two fluids. We can also assume negligible kinetic and potential. The energy balance on each fluid can be written as the rate of heat loss from the hot fluid is equal to the rate of heat gained by the cold fluid in any section of the heat exchanger:

Q = -m,h×c,ph×dT,h   (1)

where Q=rate of heat loss, m=mass flow rate, c,ph=heat capacity of the hot fluid, dT,h= differential temperature of the hot fluid

Q = m,c×c,pc×T.c  (2)

where Q=rate of heat loss, m=mass flow rate, c,ph=heat capacity of the cold fluid, dT,h= differential temperature of the cold fluid

The temperature of the hot fluid change is negative and is added to make Q positive. Solving equations 1 and 2 in terms of dT:

dT.h = - Q/(m,h×c,ph)

dT.c =  Q/(m,c×c,pc)

and taking the difference:

dT,h-dT,c= d(T,h - T,c) = -Q(1/(m,h×c,ph) + 1/(m,c×c,pc)) (3)

The heat transfer rate in the differential section of the heat exchanger can be expressed as:

Q = U(T,h-T,c)×dA,s  (4)

where U=overall heat transfer coefficients, dA,s = differential sectional area. Substitute equation 4 into 3:

d(T,h - T,c)/(T,h - T,c) = -U×dA,s×(1/(m,h×c,ph) + 1/(m,c×c,pc))  (5)

Integrating equation 5:

㏑((T,h out - T,c out)/(T,h in - T,c in)) = -U×A,s×(1/(m,h×c,ph) + 1/(m,c×c,pc))  (6)

The first law of thermodynamics requires the rate of heat transfer from hot and cold fluid to be equal.

Q= m×c, pc×(T, c out-T, c in)  (7)

Q= m×c, ph×(T,h out-T, h in)   (8)

Solve equations 7 and 8 for m,c×c, pc and m,h×c, ph and substituting into equation 6:

Q = U×A,s×ΔT,lm

Where the log mean temperature difference is:

ΔT,lm=(ΔT1-ΔT2)/㏑(ΔT1/ΔT2)

Download pdf
8 0
3 years ago
A soil weighs 2,520 lbs/CY in its in situ condition, 1,970 lb/CY in its loose condition after excavation, and 3,025 lbs/CY in an
azamat

Answer:

load factor = 0.782

Shrink Factor = 0.833

no of truck is  62500

Explanation:

given data

soil weighs in situ condition  =  2,520 lbs/CY

soil weighs in loose condition  =  1,970 lb/CY

soil weighs in embanked state = 3,025 lbs/CY

average volume = 16 LCY

soil from a borrow pit = 1 million CCY

solution

first we get here Load Factor that is express as

load factor = \frac{1,970}{2550}

load factor = 0.782

and Shrink Factor will be as

Shrink Factor = \frac{2520}{3025}

Shrink Factor = 0.833

and

no of truck will be

no of truck = \frac{1000000}{16}

no of truck is  62500

6 0
3 years ago
Other questions:
  • The 10 foot wide circle quarter gate AB is articulated at A. Determine the contact force between the gate and the smooth surface
    10·1 answer
  • A thick steel slab (rho= 7800 kg/m3 , cp= 480 J/kg K, k= 50 W/m K) is initially at 300 °C and is cooled by water jets impinging
    13·1 answer
  • A plane surface 25 cm wide has its temperature maintained at 80°C. Atmospheric air at 25°C ows parallel to the surface
    12·1 answer
  • Any one here play animal crossing new horizons<br> if so wanna play
    11·2 answers
  • Whats the best used for cable -stayed bridge
    11·1 answer
  • How much thermal energy is needed to raise the temperature of 15kg gold from 45⁰ C up to 80⁰ C​
    10·1 answer
  • An isothermal CSTR with a first order irreversible reaction A â&gt; B (and rA[mol/(ft3*min)] = - 0.5 CA) has a constant flow rat
    13·1 answer
  • An energy system can be approximated to simply show the interactions with its environment including cold air in and warm air out
    6·1 answer
  • When your fixing a car, what is the first thing you want to do?
    13·1 answer
  • 10. What refrigerant is no longer manufactured in the<br> United States?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!