Conductor sizes up through 4/0 AWG are expressed in American Wire Gauge (AWG). Conductor sizes larger than 4/0
AWG are expressed in
Explanation:
Sizes smaller than 36 AWG can be calculated in gauge, but wires larger than 4/0 are commonly expressed in 1,000 circular mils (kcmil or MCM) where one cmil is the area of a circle with a diameter of one mil (1/1,000 inch).
Conductor sizes up through 4/0 AWG are expressed in American Wire Gauge (AWG). Conductor sizes larger than 4/0
AWG are expressed in Komil
Answer:
Ts = 413.66 K
Explanation:
given data
temperature = 20°C
velocity = 10 m/s
diameter = 5 mm
surface emissivity = 0.95
surrounding temperature = 20°C
heat flux dissipated = 17000 W/m²
to find out
surface temperature
solution
we know that here properties of air at 70°C
k = 0.02881 W/m.K
v = 1.995 × m²/s
Pr = 0.7177
we find here reynolds no for air flow that is
Re =
Re =
Re = 2506
now we use churchill and bernstein relation for nusselt no
Nu = = 0.3 +
h = 0.3 +
h = 148.3 W/m².K
so
q conv = h∈(Ts- T∞ )
17000 = 148.3 ( 0.95) ( Ts - (20 + 273 ))
Ts = 413.66 K
Answer:
vertical load = 10 kN
Modulus of elasticity = 200GPa
Yield stress on the cable = 400 MPa
Safety factor = 2.0
Explanation:
Data
let L =
= 3.35 m
substituting 1.5 m for h and 3 m for the tern (a + b)
= tan⁻¹()
= 45⁰
substituting 1.5 for h and 3 m for (a+ b) yields:
₂ = tan⁻¹ ()
=25.56⁰
checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.
Answer:
The flow velocity reduces to 0.72 m/s
Explanation:
According to the equation of continuity discharge in the channel should remain same
Thus we have
For a rectangular channel we have
Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have
Answer:
a) The proportional limit is 2.99MPa.
b) The modulus of elasticity is 0.427GPa.
C) The poisson´s ratio is 0.021
Explanation:
a) The proportional limit is the maximum stress for wich a tension bar stops acting as a linear material in a stress-strain curve. So this stress can be obtained as:
b) The modulus of elasticity E is the proportion between the strain and the stress in the linear section of the stress-strain curve.
The strain in for the proportional limit is:
Therefore:
c) The Poisson´s ratio is the negative proportion between the transverse strain and axial strain.
In this case, the transverse strain is:
So the poisson´s ratio is: