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docker41 [41]
3 years ago
14

15 POINTS PLZ HELP IM ON A TIMER! IM ON EDGE EXAM

Physics
2 answers:
sleet_krkn [62]3 years ago
8 0

Answer:

B.) Pressure traps dissolved gases in magma

Explanation:

I hope this answer is correct

Anestetic [448]3 years ago
4 0

Answer:

B

Explanation:

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If the density of a substance is 5g/cm3 and the volume is 10cm3,<br> determine the mass.
vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

(5g/cm³)*(10cm³) = 50g

6 0
3 years ago
Read 2 more answers
Based on Newton’s 3rd law if you were to push on the wall with a force of 100 N, how much force would the wall push back towards
rusak2 [61]
The answer is 100N. Look up the definition of Newton's third law.
3 0
3 years ago
A car traveling 90.0 km/h is 1500 m behind a truck traveling at 76.0 km/h. 1) How long will it take the car to catch up with the
sergejj [24]
It will take about 3-5 hour
8 0
3 years ago
a stone with a mass of 2.40 kg is moving with velocity (6.60î − 2.40ĵ) m/s. find the net work (in j) on the stone if its velocit
ch4aika [34]

By the work energy theorem, the total work done on the stone is given by its change in kinetic energy,

W = \Delta K = \dfrac m2 ({v_2}^2 - {v_1}^2)

We have

\vec v_1 = (6.60\,\vec\imath - 2.40\,\vec\jmath)\dfrac{\rm m}{\rm s} \implies {v_1}^2 = \|\vec v_1\|^2 = 49.32 \dfrac{\rm m^2}{\rm s^2}

\vec v_2 = (8.00\,\vec\imath + 4.00\,\vec\jmath) \dfrac{\rm m}{\rm s} \implies {v_2}^2 = \|\vec v_2\|^2 = 80.0\dfrac{\mathrm m^2}{\mathrm s^2}

Then the total work is

W = \dfrac{2.40\,\rm kg}2 \left(80.0\dfrac{\rm m^2}{\rm s^2} - 49.32\dfrac{\rm m^2}{\rm s^2}\right)  \approx \boxed{36.8\,\rm J}

5 0
2 years ago
4. With regard to the pH scale, a solution with a pH
pentagon [3]

Answer:

A. Close to 14 is considered a strong base

Explanation:

A substance with a pH close to 14 is considered a strong base

<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>IF</em><em> </em><em>MY</em><em> </em><em>ANSWER</em><em> </em><em>IS</em><em> </em><em>HELPFUL</em><em> </em><em>;</em><em>)</em><em> </em>

5 0
3 years ago
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