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kogti [31]
3 years ago
14

1. A bicyclist travels for 1.5 hours at an average speed of 23 km/h. How far does the bicyclist travel

Physics
2 answers:
allsm [11]3 years ago
8 0

Explanation:

23 km/hr x 1.5 hrs = 34.5 km

34.5 km = 34500 meters

SOVA2 [1]3 years ago
5 0
In this case your finding d or distance. So you would have to multiply the time by speed. The time in this case is 1.5hrs, the speed in 34.5km/h. So multiply and you’ll get 34.5m
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Answer:

<em><u>Assuming that the vertical speed of the ball is 14 m/s</u></em> we found the given values:

a) V₀ = 23.4 m/s

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Explanation:

a) <u>Assuming that the vertical speed is 14 m/s</u> (founded in the book) the initial speed of the ball can be calculated as follows:  

V_{f}^{2} = V_{0}^{2} - 2gh

<u>Where:</u>

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V_{0}: is the initial speed =?

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V_{0} = \sqrt{V_{f}^{2} + 2gh} = \sqrt{(14 m/s)^{2} + 2*9.81 m/s^{2}*18 m} = 23.4 m/s  

b) The maximum height is:

V_{f}^{2} = V_{0}^{2} - 2gh

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V_{f} = V_{0} - gt

t = \frac{V_{0} - V_{f}}{g} = \frac{23.4 m/s - 14 m/s}{9.81 m/s^{2}} = 0.96 s

d) The flight time is given by:

t_{v} = \frac{2V_{0}}{g} = \frac{2*23.4 m/s}{9.81 m/s^{2}} = 4.8 s

         

I hope it helps you!    

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