<span>C) 4.5 billion years old</span>
When an object falls or is dropped from rest it's initial velocity is zero.
Using the equations for a motion in straight line. I can find the time it takes to reach 3.0 m down (half way).
x = vt - 4.9t²
-3 = 0 - 4.9t²
-3/-4.9 = t²
0.6122 = t²
0.7825 sec = t
v = v - gt
v = 0 - 9.8(0.7825)
v = -7.67 m/s
the negative denotes downward direction.
You could also solve the problem using potential and kinetic energy.
Since it starts with maximum PE and gets converted to KE when it hits the ground. mgh = mv²/2
mass cancels, use 3 meters for the halfway distance
-9.8(-3) = v²/2
29.4 * 2 = v²
√(58.8) = 7.67 m/s downwards
A manufacturer of printed circuit boards has a design
capacity of 1,000 boards per day. the effective capacity, however, is 700
boards per day. recently the production facility has been producing 950 boards
per day. The design capacity utilization is (950/100) *100 = 95 %
1) Size of the image: 2 cm
In order to calculate the size of the image, we can use the following proportion:
where
p = 80 m is the distance of the tree from the pinhole
q = 20 cm = 0.2 m is the distance of the image from the pinhole
= 8 m is the heigth of the object
is the height of the image
By re-arranging the proportion, we find
2) Magnification: 0.0025
The magnification of a camera is given by the ratio between the size of the image and the size of the real object:
so, in this problem we have
