Answer:
57.48%
Explanation:
Calculate the mass of 1 mole of malachite:
MM Cu = 63.55
MM O = 16.00
MM H = 1.01
MM C = 12.01

A mole of malachite has:
2 moles of Cu
5 moles of O
2 moles of H
1 mole of C
MW Malachite = 2*MM(CU) + 5*MM(O) + 2*MM(H) + 1 *MM(C)
MW Malachite = 2*63.55 + 5*16.00 + 2*1.01 + 1*12.01
MW Malachite = 221.13
Mass of Cu in a mole of Malachite = 2*MM(CU) = 127.1
Now divide the mass of Cu by the mass of Malachite

Answer:
They include frequency, period,speed,amplitude and phase
The minimum volume of 0.2M sodium sulfide that will precipitate out aluminum from 50.0 mL, 0.25 M aluminum nitrate would be 0.094 L or 94 mL
<h3>Stoichiometric calculation</h3>
From the equation of the reaction:

Mole ratio of Na2S and Al(NO3)3 = 3:2
Mole of 50.0 mL, 0.25 M Al(NO3)3 = 50/1000 x 0.25
= 0.0125 mole
Equivalent mole of Na2S = 3/2 x 0.0125
= 0.0188 mole
Volume of 0.2M, 0.0188 mole Na2S = 0.0188/0.2
= 0.094 L or 94 mL
More on stoichiometric calculations can be found here: brainly.com/question/8062886
Answer is: pKa for the
monoprotic acid is 5.<span>
Chemical reaction: HA(aq) </span>⇄ A⁻(aq) + H⁺<span>(aq).
c(monoprotic acid) = 0.100 M.
pH = 3.00.
[A</span>⁻] = [H⁺] = 10∧(-3).<span>
[A</span>⁻]
= [H⁺] = 0.001 M; equilibrium concentration.<span>
[HA] = 0.1 M - 0.001 M.
[HA] = 0.099 M.
Ka = [A</span>⁻]·[H⁺] / [HA].<span>
Ka = (0.001 M)² / 0.099 M.
Ka = 0.00001 M = 1.0·10</span>⁻⁵ M.
<span>pKa = -logKa = 4.99.
</span>
<span>An Inference Is An Idea Or Conclusion Thats Drawn From Evidence And Reasoning. An Inference Is Also An Educated Guess.</span>