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Tema [17]
2 years ago
12

Explain what happens in the reaction between sodium hydroxide and hydrochloric acid.Explain how protons are donated and accepted

.
Chemistry
1 answer:
Artyom0805 [142]2 years ago
7 0

Answer:

<em><u>Hydrochloric acid and sodium hydroxide interact, resulting in salt and a release of heat. As we can see, the result of the interaction of two highly aggressive compounds is table salt and water – compounds that are ultimately harmless, even beneficial, to human beings.</u></em>

<em><u>2</u></em><em><u>)</u></em><em><u> </u></em><em><u>An acid is a substance that donates protons (in the Brønsted-Lowry definition) or accepts a pair of valence electrons to form a bond (in the Lewis definition). A base is a substance that can accept protons or donate a pair of valence electrons to form a bond.</u></em><em><u>A base is a substance that can accept protons or donate a pair of valence electrons to form a bond. Bases can be thought of as the chemical opposite of acids. A reaction between an acid and base is called a neutralization reaction.</u></em>

Explanation:

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<em><u>If</u></em><em><u> </u></em><em><u>helped</u></em><em><u> </u></em><em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>Brainleist</u></em><em><u> </u></em>

<em><u>Have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good </u></em><em><u>night</u></em><em><u> </u></em><em><u>ahead</u></em><em><u> </u></em><em><u>✌️</u></em>

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Answer:

C. CH3COOH, Ka = 1.8 E-5

Explanation:

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We choose the (C) acid since its pKa close to the expected pH.

⇒ For a buffer solution formed from an acid and its respective salt, we have the equation Henderson-Hausselbach (H-H):

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∴ pH = 4.5

∴ pKa = 4.745

⇒ 4.5 = 4.745 + Log ([CH3COO-]/[CH3COOH])

⇒ - 0.245 = Log ([CH3COO-]/[CH3COOH])

⇒ 0.5692 = [CH3COO-]/[CH3COOH]

∴ Ka = 1.8 E-5 = ([H3O+].[CH3COO-])/[CH3COOH]

⇒ 1.8 E-5 = [H3O+](0.5692)

⇒ [H3O+] = 3.1623 E-5 M

⇒ pH = - Log ( 3.1623 E-5 ) = 4.5

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