Genetic information, such as DNA, will dictate or control the characteristics that an organism will have.
Answer:
X ray
Explanation:
To see an object the light used must have the same or smaller wavelength than the object. The size of an atom is about
m, smaller than the wavelength, therefore we'll need radiation with a shorter wavelength <em>since X-ray wavelengths are about the same size as atoms this characteristic makes it ideal to use.</em>
I hope you find this information useful nd interesting! Good luck!
Answer:

Explanation:
The water droplet is initially neutral, it will obtain a 40 nC of charge when a charge of -40 nC is removed from the water droplet.
The charge on one electron, 
Let the N number of electrons have charge -40 nC, such that,
Now, mass of one electron = 
Therefore, mass of N electrons = 
It is the mass of the of the water droplet that must be removed in order to obtain a charge of 40 nC.
Let it is m times the total mass of the droplet which is 
Then,

It is the required fraction of mass of the droplet.
Answer:
P = 15.90 W
Explanation:
given,
speed of conveyor belt = 0.56 m/s
conveyor belt move up to = 2 m
angle made with the horizontal = 15°
mass of the box = 2.1 kg
rate is the force of the conveyor belt doing work on the box as the box moves up
P = F v cos ∅
P = 3 × 9.8 × 0.56 × cos 15°
P = 15.90 W
Answer:
The mass is 
Explanation:
From the question we are told that
The extension of the rod is 
The area is 
The density increase as follows 
The equation 
at

So

=> 
So at
, 
So

=> 
Now

![m = 8 [{2.5 +\frac{ 1.27x^2}{2} } ]\left | 13} \atop {0}} \right.](https://tex.z-dn.net/?f=m%20%20%3D%20%208%20%20%20%5B%7B2.5%20%2B%5Cfrac%7B%201.27x%5E2%7D%7B2%7D%20%7D%20%5D%5Cleft%20%20%7C%2013%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
![m = 8 [{2.5 +\frac{ 1.27(13)^2}{2} } ]](https://tex.z-dn.net/?f=m%20%20%3D%20%208%20%20%20%5B%7B2.5%20%2B%5Cfrac%7B%201.27%2813%29%5E2%7D%7B2%7D%20%7D%20%5D)

