Answer:
vb = 22.13 m/s
So, the only thing that was measured here was the height of point A relative to point B. And the Law of Conservation of Energy was used.
Explanation:
In order to find the speed of roller coaster at Point B, we will use the law of conservation of Energy. In this situation, the law of conservation of energy states that:
K.E at A + P.E at A = K.E at B + P.E at B
(1/2)mvₐ² + mghₐ = (1/2)m(vb)² + mg(hb)
(1/2)vₙ² + ghₐ = (1/2)(vb)² + g(hb)
where,
vₙ = velocity of roller coaster at point a = 0 m/s
hₙ = height of roller coaster at point a = 25 m
g = 9.8 m/s²
vb = velocity of roller coaster at point B = ?
hb = Height of Point B = 0 m (since, point is the reference point)
Therefore,
(1/2)(0 m/s)² + (9.8 m/s²)(25 m) = (1/2)(vb)² + (9.8 m/s²)(0 m)
245 m²/s² * 2 = vb²
vb = √(490 m²/s²)
<u>vb = 22.13 m/s</u>
<u>So, the only thing that was measured here was the height of point A relative to point B. And the Law of Conservation of Energy was used.</u>
<span>In Coulomb's law, however, the
magnitude and sign of the electric force are determined by the electric
charge, rather than the mass, of an object. ... Thus, two negative
charges repel one another, while a positive charge attracts a negative
charge. The attraction or repulsion acts along the line between the two charges</span>
Answer:
15m/s²
Explanation:
According to Newton's second law;
Force = mass * acceleration
Given
Force = 1.5N
mass = 0.10kg
Required
acceleration
Substitute into the expression;
1.5 = 0.1a
a = 1.5/0.1
a = 15m/s²
Hence the acceleration that the puck move across the air table is 15m/s²