Answer:
uk = 0.25
Explanation:
Given:-
- An object comes to stop with acceleration, a = -2.45 m/s^2
Find:-
What is the coefficient of kinetic friction between the object and the floor?
Solution:-
- Assuming the object has mass (m) that slides over a rough surface with coefficient of kinetic friction (uk). There is only Frictional force (Ff) acting in the horizontal axis on the object opposing the motion (-x direction).
- We will apply equilibrium equation on the object in vertical direction.
N - m*g = 0
N = m*g
Where, N : Contact force exerted by the surface on the floor
g : Gravitational acceleration constant = 9.81 m/s^2
- Now apply Newton's second law of motion in the horizontal ( x-direction ):
- Ff = m*a
- The frictional force is related to contact force (N) by the following expression:
Ff = uk*N
- Substitute the 1st and 3rd expressions in the 2nd equation:
uk*m*g = -m*a
uk = a / g
- Plug in the values and solve for uk:
uk = - (-2.45) / 9.81
uk = 0.25
a single two-dimensional cross-sectional imagine made using real-time technology
<u>Answer:</u>
<em>The correct equation for measuring the average microscopic weight for 3 isotopes is multiply the rate of abundance by each weight and add them.</em>
<u>Explanation:</u>
To calculate the average microscopic mass of element using weights and relative abundance we have to follow the following steps.
- Take the correct weight of each isotope (that will be in decimal form)
- Multiply the weight of each isotope by its abundance
- Add each of the results together.
<em>This gives the required average microscopic weight of the three isotopes.</em>
Answer:
Part a)
Part b)
Explanation:
Let say the extension of spring 1 is x1 and extension of spring 2 is x2
then we will have
so we will have
for other spring we will have
so total extension of both the springs is given as
Part b)
Let say the effective spring constant is k
so we will have