In metallurgy, non-ferrous metals are metals or alloys that do not contain iron in appreciable amounts. Generally more costly than ferrous metals, non-ferrous metals are used because of desirable properties such as low weight, higher conductivity, non-magnetic property or resistance to corrosion
Answer:
a)
Calculate the net power developed by using
the following relation:
Wste=W-W.
Substitute 8728 kw for w, and 2846 kw for w..
Wyle=8728 - 2846
= 5882 kW
Therefore, the net power developed is 5882 kW).
Comment
Step 6 of 7 A
Calculate the thermal efficiency by using the
following relation:
Here, e, is the heat input.
Substitute w, for ..
w
Substitute s882 kw for ws and 8728 kw for w.
5882
1-8728
67.39%
Therefore, the thermal efficiency is 67.39%).
Comments (3)
Step 7 of 7 A
Calculate the back work ratio.
bwr =
Substitute 8728 kw for w, and 2846 kw for w..
bwr - 2846
bwr=8728
=0.326
Therefore, the back work ratio is 10.326).
Explanation:
Answer:
Estimated number of indigenous faults remaining undetected is 6
Explanation:
The maximum likelihood estimate of indigenous faults is given by,
here,
= the number of unseeded faults = 6
= number of seeded faults = 30
= number of seeded faults found = 15
So NF will be calculated as,
And the estimate of faults remaining is 
= 12 - 6 = 6
Answer:
A degree in architecture with 60 credit hours.
Explanation:
The requirements need for a student to qualify for a two year master of architecture degree are;
- 60 credit hours in architecture
- Complete 60 credit hours in related area of profession such as; planning, landscape architecture ,public health and others.
- 45 credit hours in architecture course at the level of 500/600
Answer:
distance = 22.57 ft
superelevation rate = 2%
Explanation:
given data
radius = 2,300-ft
lanes width = 12-ft
no of lane = 2
design speed = 65-mph
solution
we get here sufficient sight distance SSD that is express as
SSD = 1.47 ut + 
..............1
here u is speed and t is reaction time i.e 2.5 second and a is here deceleration rate i.e 11.2 ft/s² and g is gravitational force i.e 32.2 ft/s² and G is gradient i.e 0 here
so put here value and we get
SSD = 1.47 × 65 ×2.5 + 
solve it we get
SSD = 644 ft
so here minimum distance clear from the inside edge of the inside lane is
Ms = Rv ( 1 - 
) .....................2
here Rv is = R - one lane width
Rv = 2300 - 6 = 2294 ft
put value in equation 2 we get
Ms = 2294 ( 1 - 
)
solve it we get
Ms = 22.57 ft
and
superelevation rate for the curve will be here as
R = 
..................3
here f is coefficient of friction that is 0.10
put here value and we get e
2300 = 
solve it we get
e = 2%
