1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iogann1982 [59]
3 years ago
9

A cylindrical metal specimen having an original diameter of 12.8 mm and gauge length of 50.80 mm is pulled in tension until frac

ture occurs. The diameter at the point of fracture is 6.60 mm (0.260 in.), and the fractured gauge length is 72.14 mm. Calculate the ductility in terms of percent reduction in area and percent elongation.
Engineering
1 answer:
Sedaia [141]3 years ago
3 0

Answer:

%Reduction in area = 73.41%

%Reduction in elongation = 42.20%

Explanation:

Given

Original diameter = 12.8 mm

Gauge length = 50.80mm

Diameter at the point of fracture = 6.60 mm (0.260 in.)

Fractured gauge length = 72.14 mm.

%Reduction in Area is given as:

((do/2)² - (d1/2)²)/(do/2)²

Calculating percent reduction in area

do = 12.8mm, d1 = 6.6mm

So,

%RA = ((12.8/2)² - 6.6/2)²)/(12.8/2)²

%RA = 0.734130859375

%RA = 73.41%

Calculating percent reduction in elongation

%Reduction in elongation is given as:

((do) - (d1))/(d1)

do = 72.14mm, d1 = 50.80mm

So,

%RA = ((72.24) - (50.80))/(50.80)

%RA = 0.422047244094488

%RA = 42.20%

You might be interested in
A metal alloy has been tested in a tensile test with the following results for the flow curve
MA_775_DIABLO [31]

Answer:

dhjdjs

Explanation:

ehejsikajaudiieisisjsjsjsjsjjsjsjsjsjs

4 0
2 years ago
One - tenth kilogram of air as an ideal gas with k= 1.4 executes a carnot refrigeration cycle as shown i fig. 5,16, the isotherm
maria [59]

Answer:

Hello your question is incomplete attached below is the missing part

a) p1 = 454.83 kPa,  p2 = 283.359 Kpa , p3 = 536.423 kpa , p4 = 860.959kPa

b) W12 = 3.4 kJ, W23 = -3.5875 KJ, W34 = -4.0735 KJ, W41 = 3.5875 KJ

c) 5

Explanation:

Given data:

mass of air ( m ) = 1/10 kg

adiabatic index ( k ) = 1.4

temperature for isothermal expansion = 250K

rate of heat transfer ( Q12 ) = 3.4 KJ

temperature for Isothermal compression ( T4 ) = 300k

final volume ( V4 ) = 0.01m ^3

a)  Calculate the pressure, in Kpa, at each of the four principal states

from an ideal gas equation

P4V4 = mRT4 ( input values above )

hence P4 = 860.959kPa

attached below is the detailed solution

b) Calculate work done for each processes

attached below is the detailed solution

C) Calculate the coefficient of performance

attached below is detailed solution

6 0
2 years ago
Tech A says that a transistor has a single P–N junction. Tech B says that a transistor is a semiconductor device used as a switc
Aloiza [94]

Answer:

Both Technician A and technician B are correct.

Explanation: A transistor must have a P-N junction as that is where the positive and negative charges are connected.

A transistor also can be described as a semiconductor which acts as a switch and can be used to amplify currents. Transistors are very key and vital to electronic devices especially the mobile phones in recent times, it helps to ensure that electronic systems perform optimally.

The charges in the P-N junction is controlled by the availability of Positive and negative electrons.

6 0
3 years ago
A plane wall of length L, constant thermal conductivity k and no thermal energy generation undergoes one-dimensional, steady-sta
KIM [24]

Answer:

Temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

Heat rate=q A  

Explanation:

We know that for no heat generation and at steady state

\dfrac{\partial^2 T}{\partial x^2}=0

\dfrac{\partial T}{\partial x}=a

T(x)=ax+b

a and are the constant.

Given that heat flux=q

We know that heat flux given as

q=-K\dfrac{dT}{dx}

From above we can say that

a= -\dfrac{q}{K}

Alos given that when x= L temperature is T(L)=T

T= -\dfrac{q}{K}L+b

b=T+\dfrac{q}{K}L

So temperature T(x)

T(x)=-\dfrac{q}{K}x+T+\dfrac{q}{K}L

T(x)=\dfrac{q}{k}(L-x)+T

So temperature distribution is T(x)=\dfrac{q}{k}(L-x)+T

Heat flux=q

Heat rate=q A         (where A is the cross sectional area of wall)

   

6 0
3 years ago
Which of the following distinguishes a reservoir from an accumulator?
lozanna [386]

Answer:

Reservoirs usually have zero pressure

Explanation:

accumulators are controlled by pressure valves while reservoirs are not

accumulators "accumulate" pressure while reservoirs are used to store "overflow" fluids for later use if needed

6 0
2 years ago
Other questions:
  • Does a food market have any rooms in particular? Also whats units?
    10·2 answers
  • 2. In the above figure, what type of cylinder arrangement is shown in the figure above?
    9·1 answer
  • A piston cylinder assembly fitted with a slowly rotating paddle wheel contains 0.13 kg of air at 300K. The air undergoes a const
    10·1 answer
  • Please Help It's really Important
    12·1 answer
  • What is Pressure measured from absolute zero pressure called?
    14·1 answer
  • Technician A says the final drive assembly always has a gear ratio of 1:1. Technician B says the final drive assembly provides f
    11·1 answer
  • Breaks do not overheat true false ?
    6·1 answer
  • Traffic at a roundabout moves
    8·1 answer
  • Typically each development platform consists of the following components, except:Select one:a.Operating systemb.System softwarec
    8·1 answer
  • Which organization would provide business and leadership training to a high school hospitality student?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!