Answer:
a. 4900 mL; b. 4900 cm³ c. 4.9x10⁻³ m³
Explanation:
1 L = 1 dm³
4.9 L = 4.9 dm³
1 dm³ = 1000 cm³ → 4900 cm³
1 cm³ = 1 mL (4900 mL)
1 dm³ = 1x10⁻³ m³ → 4.9x10⁻³ m³
Answer:
The heat absorbed by water is 39243.75 J.
Explanation:
Given data:
Mass of water = 375.0 g
Heat absorbed by water= ?
Initial temperature = 10.0°C
Final temperature = 35.0 °C
The specific heat capacity of water = 4.186 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 10°C
ΔT = 25°C
Q = m.c. ΔT
Q = 375.0 g× 4.186 j/g °C × 25°C
Q = 39243.75 J
The heat absorbed by water is 39243.75 J.
Answer:
Hexose category and ketohexose category
Explanation:
The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category
Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category
Attached below is the remaining part of the solution
b.) mixtures are made up of more than on component. A pure substance is like a diatomic element, like O2, while a mixture is more like a salad, and can be separated by physical means.
Answer:
Urea contains more nitrogen
Explanation:
1 mole of Urea contains 2 moles of Nitrogen and 1 mole of ammonium sulfate contains, also, 2 moles of nitrogen.
60g of urea (Molar mass: 60g/mol) contains:
60g × (1mol / 60g) = 1 mole. As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 2.
100g of ammonium sulfate (Molar mass: 132g/mol) contains:
100g × (1mol / 132g) = 0.758 moles.
As 1 mole of urea contains 2 moles of nitrogen, moles of nitrogen are 0.758×2 = 1.516 moles.
That means, <em>urea contains more nitrogen</em>.
