Momentum = (mass) x (speed)
Change in momentum = (force) x (time)
The initial momentum is (mass) x (speed) = 2500x 25 = 62,500 kg-m/s.
Since you want to <u>stop</u> the vehicle, that number is also the required <em>change</em>
in momentum ... you want the vehicle to wind up with zero momentum.
62,500 = (force) x (time) = 20 x force
Divide each side by 20 :
force = 62,500 / 20 = <em>3,125 newtons </em>
Answer:
The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Explanation:
Given that,
Atomic number = 20
The configuration of Ca

So, The principle quantum number is n =4.
The azimuthal quantum number can take value from 0,1,2...(n-1)
In the ground state, l= 0
When it is excited to p state
Then, l = 1
The magnetic quantum number can take value from l to -l

Hence, The possible quantum numbers for Ca atom when it is in excited
n = 4
l= 1
m =-1,0,1
Answer:
The square of the hypotenuse is equal to the sum of the squares of the other two lengths.
Explanation:
only one that made sense
In order to see what's going on, let's put them in empty space to get rid of any other influences, and let's also make it a push instead of a pull. / / / The horse pushes on the cart, so it begins accelerating away from him. At the same time, because of the equal opposite reaction thing, the cart pushes back on the horse, so the horse starts accelerating backwards, away from the cart. They both accelerate in opposite directions from where they started. BUT . . . their common center of mass doesn't move, and the sum of their momentums (which are in opposite directions) remains zero.