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VladimirAG [237]

3 years ago

14

Differentiate scalar & vector quantity?

1 answer:

Keith_Richards [23]3 years ago

5 0

$\textbf{Hello Friend}$

Scalar Quantity :-

→ These are the quantities with magnitude only . These quantities doesn't have to be mentioned with direction

eg.)=> Mass , Temprature .

Vector Quantity :-

→ These quantities are described with both Magnitude and Direction . These quantities follow special type of algebra called Vector algebra .

eg.)=> Force , Displacement

_______________________________

Hope It Helps You. ☺

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You hold a spherical salad bowl 50 cm in front of your face with the bottom of the bowl facing you. The salad bowl is made of po

nataly862011 [7]

Answer:

a) q = 39.29 cm , b) h ’= - 3.929 cm the image is inverted and REAL

Explanation:

For this exercise we will use the equation of the constructor

1 / f = 1 / p + 1 / q

where f is the focal length of the salad bowl, p and q are the distance to the object and the image

The metal salad bowl behaves like a mirror, so its focal length is

f = R / 2

f = 44/2

f = 22 cm

a) Suppose that the distance to the object is p = 50 cm, let's find the distance to the image

1 / q = 1 / f - 1 / p

1 / q = 1/22 - 1/50

1 / q = 0.0254

q = 39.29 cm

b) to calculate the size of the image we use the equation of magnification

m = h’/ h = - q / p

h ’= - q / p h

h ’= - 39.29 / 50 5

h ’= - 3.929 cm

the negative sign means that the image is inverted

as the rays of light pass through the image this is REAL

4 0

4 years ago

In Millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are

alina1380 [7]

Answer:

$-9.6\cdot 10^{-19} C$

Explanation:

The charge of a single electron is:

$q=-1.60\cdot 10^{-19} C$

If a droplet contains N electrons, then its charge would be:

$Q=Nq$

In this case, the droplet has

N = 6

electrons, so its total charge is

$Q=(6)(-1.60\cdot 10^{-19}C)=-9.6\cdot 10^{-19} C$

7 0

3 years ago

Two long, parallel wires are separated by a distance of 2.2 cm. The force per unit length that each wire exerts on the other is

VikaD [51]

Answer:

$i_2 = 7.6 A$

Explanation:

As we know that the force per unit length of two parallel current carrying wires is given as

$F = \frac{\mu_o i_1 i_2}{2\pi d}$

here we know that

$F = 3.6 \times 10^{-5} N/m$

$i_1 = 0.52 A$

d = 2.2 cm

now from above equation we have

$3.6 \times 10^{-5} = \frac{4\pi \times 10^{-7} (0.52)(i_2)}{2\pi (0.022)}$

$3.6 \times 10^{-5} = 4.73 \times 10^{-6} i_2$

$i_2 = 7.6 A$

5 0

3 years ago

PLEASE ANSWER!!! WILL GIVE BRAINLIEST!!!!!

Kipish [7]

Answer:

the ability to do work.

EXPLAINATION: .

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