There are 500 mg of calcium carbonate is in this caltrate tablet
The equation of the reaction is;
2HCl(aq) + CaCO3(aq) ------> CaCl2(aq) + CO2(g) + H2O(l)
Next, we have to obtain the amount HCl reacted as follows;
Number of moles = concentration × volume
Volume = 34.46 mL or 0.03446 L
Concentration = 0.291 M
Number of moles = 0.291 M × 0.03446 L
Number of moles = 0.01 moles
Since the reaction of HCl and CaCO3 are in the ratio of 2:1
2 moles of HCl reacts with 1 mole of CaCO3
0.01 moles of HCl reacts with 0.01 moles × 1 mole/2 moles
= 0.005 moles of CaCO3
Mass of CaCO3 = number of moles × molar mass
Mass of CaCO3 = 0.005 moles of CaCO3 × 100 g/mol
Mass of CaCO3 = 0.5 g or 500 mg
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