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Serga [27]
2 years ago
11

What quantity in moles of CH₂OH are there in 150.0 mL of 0.210 M CH₂OH?

Chemistry
1 answer:
Aleks [24]2 years ago
3 0

Answer:

0.0315 moles CH₂OH

Explanation:

You can find the amount of moles using the molarity equation. This equation looks like this:

Molarity (M) = moles / volume (L)

Once you convert mL to L (by dividing by 1,000), you can plug the molarity and volume into the equation and isolate to find moles. The final answer should have 3 sig figs because the given value with the lowest amount of sig figs (0.210 M) has this amount.

150.0 mL / 1,000 = 0.1500 L

Molarity = moles / volume

0.210 M = moles / 0.1500 L

(0.210 M x 0.1500 L) = moles

0.0315 = moles

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General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Using Dimensional Analysis
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Explanation:

<u>Step 1: Define</u>

8.32 × 10²⁴ molecules CO₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

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<u />8.32 \cdot 10^{24} \ molecules \ CO_2(\frac{1 \ mol \ CO_2}{6.022 \cdot 10^{23} \ molecules \ CO_2} ) = 13.816 mol CO₂

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