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Serga [27]
1 year ago
11

What quantity in moles of CH₂OH are there in 150.0 mL of 0.210 M CH₂OH?

Chemistry
1 answer:
Aleks [24]1 year ago
3 0

Answer:

0.0315 moles CH₂OH

Explanation:

You can find the amount of moles using the molarity equation. This equation looks like this:

Molarity (M) = moles / volume (L)

Once you convert mL to L (by dividing by 1,000), you can plug the molarity and volume into the equation and isolate to find moles. The final answer should have 3 sig figs because the given value with the lowest amount of sig figs (0.210 M) has this amount.

150.0 mL / 1,000 = 0.1500 L

Molarity = moles / volume

0.210 M = moles / 0.1500 L

(0.210 M x 0.1500 L) = moles

0.0315 = moles

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jeka94

Answer:

heat energy are absorbed by water molecules and it is used to change the molecules from liquid to gas? if thats what your asking.

Explanation:

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3 years ago
What type of scientific inquiry is friction ridge analysis
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Answer:

Towards this goal, this project aims to develop a statistical measure of the uncertainty of the decisions made on the friction ridge evidence (i.e., evidential value of fingerprint comparison), which ultimately can be referred to as a scientific basis of the identification decisions made in friction ridge analysis.

Explanation:

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Read 2 more answers
Tungsten (W) and chlorine (Cl) form a series of compounds with the following compositions:_______.
deff fn [24]

Answer:

WCl₂, WCl₄, WCl₅, WCl₆

Explanation:

Molar Mass of Tungsten = 184 g/mol

Mass of Chlorine = 35.5 g/mol

In the first compound;

Percentage of tungsten = 72.17 %

Upon solving;

72.17 % = 184

100 % = Total mass

Total mass of compound = 254.95g

Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.

The Formular is WCl₂

In the second compound;

Percentage of tungsten = 56.45 %

Upon solving;

56.45 % = 184

100 % = Total mass

Total mass of compound = 325.95 g

Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.

The Formular is WCl₄

In the third compound;

Percentage of tungsten = 50.91 %

Upon solving;

50.91 % = 184

100 % = Total mass

Total mass of compound = 361.42 g

Mass of chlorine =  361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.

The Formular is WCl₅

In the fourth compound;

Percentage of tungsten = 46.39 %

Upon solving;

46.39 % = 184

100 % = Total mass

Total mass of compound = 396.64 g

Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.

The Formular is WCl₆

4 0
3 years ago
How do metals and nonmetals differ in terms of how they lose/gain electrons?
Serhud [2]
Metals lose electrons
Non metals gain electrons

They do this to gain a full outer shell in order to become stabilised
4 0
3 years ago
ANSWER THIS AND YOU WILL BE THE BRAINEST!!!!!!!
Alenkasestr [34]
<h3>Answer:</h3>

               Option-B (Halide; oxide) is the correct answer.

<h3>Explanation:</h3>

                  <em> Halides</em> are those substances which contains negatively charged halide ion i.e. X⁻.

Examples:  F⁻ (Fluoride) , Cl⁻ (Chloride) , Br⁻ (Bromide) , I⁻ (Iodide) e.t.c.

                   <em>Oxides </em>are those substances which atleast containn one Oxygen atom.

Examples:  FeO (Iron Oxide), Cr₂O₃ (Chromium Oxide)

                   <em>Silicates</em> are those anionic substances which contains silicon and oxygen with general formula  [SiO. 4−x] n.

Examples: [SiO₄]⁻⁴ (Nasosilicate) , [Si₂O₇]⁻⁶ (Sorosilicates)

                   <em>Carbonates </em>are those substances which contains carbonate anion i.e. CO₃²⁻.

Examples:  Na₂CO₃ (Sodium Carbonate) , MgCO₃ (Magnesium Carbonate)

<h3>Conclusion:</h3>

                   As in NaCaAlF, F⁻ is present hence, it is an Halide and the presence of O in FeCrO makes it Oxide.

5 0
3 years ago
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