If a car accelerates from 0 to 10 m/s in 4 seconds, and the mass of the car is 1500 kg. What force is created by the car?

Think about the various energy sources such as the sun, fossil fuels, water, wind, and nuclear power. What is the energy source

lakkis [162]

Answer:

The energy source that powers my home is gotten from burning of fossil fuels.

No! I do not like this energy source.

I personally would prefer solar source of electricity

Explanation:

Fossil fuels are fuels gotten from the decomposition of dead organisms over time, under intense heat and pressure. They are usually found buried beneath the earth's crust where they have been formed and trapped.

Most electricity generating stations generate electricity by burning fossil fuels like natural gas and gasoline to generate electricity. The problem with fossil fuels are the various part that they play in increasing carbon footprints in the atmosphere. The excess carbon in the atmosphere has been a major contributor to the global warming of planet Earth.

My preference for solar energy source is first due to its abundance unlike the fossil fuels that are already diminishing in storage beneath the earth's crust. Also, solar energy is a clean source of energy that does not leave any damage on earth from its use. It also promises to be a cheap source of power in the future with advances in solar technologies.

8 0

3 years ago

Derive the equation of motion of the block of mass m1 in terms of its displacement x. The friction between the block and the sur

Alenkasestr [34]

Answer:

the equivalent mass : $m_e = m_1+m_2+\frac{I}{R^2}$

the equation of the motion of the block of mass $m_1$ in terms of its displacement is = $(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

Explanation:

Let use m₁ to represent the mass of the block and m₂ to represent the mass of the cylinder

The radius of the cylinder be = R

The distance between the center of the pulley to center of the block to be = x

Also, the angles of inclinations of the cylinder and the block with respect to the ground to be $\phi$ and $\beta$ respectively.

The velocity of the block to be = v

The equivalent mass of the system = $m_e$

In the terms of the equivalent mass, the kinetic energy of the system can be written as:

$K.E = \frac{1}{2} m_ev^2$ --------------- equation (1)

The angular velocity of the cylinder = $\omega$ : &

The inertia of the cylinder about its center to be = I

The angular velocity of the cylinder can be written as:

$v = \omega R$

$\omega =\frac{v}{R}$

The kinetic energy of the system in terms of individual mass can be written as:

$K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I\omega^2$

By replacing $\omega$ with $\frac{v}{R}$ ; we have:

$K.E = \frac{1}{2}m_1v^2+\frac{1}{2} m_2v^2+\frac{1}{2}I(\frac{v}{R})^2$

$K.E = \frac{1}{2}(m_1+ m_2+ \frac{I}{R} )v^2$ ------------------ equation (2)

Equating both equation (1) and (2); we have:

$m_e = m_1+m_2+\frac{I}{R^2}$

Therefore, the equivalent mass : $m_e = m_1+m_2+\frac{I}{R^2}$ which is read as;

The equivalent mass is equal to the mass of the block plus the mass of the cylinder plus the inertia by the square of the radius.

The expression for the force acting on equivalent mass due to the block is as follows:

$f_{block }=m_1gsin \beta$

Also; The expression for the force acting on equivalent mass due to the cylinder is as follows:

$f_{cylinder} = m_2gsin \phi$

Equating the above both equations; we have the equation of motion of the equivalent system to be

$m_e \bar x = f_{cylinder}-f_{block}$

which can be written as follows from the previous derivations

$(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

Finally; the equation of the motion of the block of mass $m_1$ in terms of its displacement is = $(m_1+m_2+\frac{I}{R^2} )(\bar x) = (m_2gsin \phi) -(m_1gsin \beta)$

8 0

3 years ago

"A boat that can travel at 4.0 km/h in still water crosses a river with a current of 2.0 km/h. At what angle must the boat be po

IRISSAK [1]

Answer:

30 degrees

Explanation:

8 0

3 years ago

7. A car moving at 10m/s (about 22.4 mph) crashes into a barrier and stops in 0.25 m.

Galina-37 [17]

Answer:

a) 0.05s

b) 4000N

Explanation:

a)When car is stopped its final velocity become zero

U- 10 m/s

V- 0 m/s

S - 0.25 m

t -?

S = (v+u)*t/2

0.25 =(10+0)*t/2

t = 0.05s

b) If we happened to calculate the avarage force we have to consider about acceleration

V= 0

U = 10

t = 0.05 s

a =?

V = U + at

0 = 10 -a * 0.05

a = 200 m/s2

F = m *a

= 20 * 200

= 4000N

6 0

3 years ago

The retina of the eye does all of the following except __________.

zvonat [6]

Answer:

C. rollback

Explanation:

The retina of the eye is located inside the eye making it impossible for the retina to roll back. Only the eye itself can rollback.

8 0

3 years ago

If a car accelerates from 0 to 10 m/s in 4 seconds, and the mass of the car is 1500 kg. What force is created by the car?​

If a car accelerates from 0 to 10 m/s in 4 seconds, and the mass of the car is 1500 kg. What force is created by the car?