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2 years ago

Why are ionized gases typically only found in very high-temperature environments?

Physics

1 answer:

LenaWriter [7]2 years ago

7 0

Explanation:

<u>Ionized gases are found in very high - temperature environment - </u>

In order to ionize a gas , i.e. to pull out an electron from a neutral atom , to form an ion .

The process of ionization require high amount of energy to remove the electron from the outer most shell of the atom .

The amount of energy for the process of ionization is only possible in high - temperature regions .

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A tennis ball is thrown against a vertical concrete wall that is fixed to the ground. The ball bounces off the wall. How does th

cestrela7 [59]

Answer:

Explanation:

The forces compare together as a result of the fact that the force exerted by that of the ball and the force exerted by that of the wall both have the same magnitude.

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3 years ago

Imagine that you drop an object of 10 kg, how much will be the acceleration and

Lelu [443]

If you do this on Earth, then the acceleration of the falling object is 9.8 m/s^2 ... NO MATTER what it's mass is.

If its mass is 10 kg, then the force pulling it down is 98.1 Newtons. Most people call that the object's "weight".

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2 years ago

A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coeff

Trava [24]

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

4 0

1 year ago

A batter hits a ball and it is caught 4 seconds later 100 m from home plate. What is the initial velocity (vector!!!) of the bal

Eddi Din [679]

Answer:

The initial velocity vector of the ball is;

$\underset{u}{\rightarrow}$ = 25·i + 19.6·j

Explanation:

The given parameters are;

The time of flight of the ball = 4 seconds

The horizontal distance from the plate at which the ball is caught = 100 m

Let 'u', represent the initial velocity, we have;

u × cos(θ) × t = u × cos(θ) × 4 s = 100 m

u × cos(θ) = 25 m/s...(1)

$t = \dfrac{2 \cdot u \cdot sin(\theta)}{g} = \dfrac{2 \cdot u \cdot sin(\theta)}{9.8 \ m/s^2} = 4 \ seconds$

∴ 2·u·sin(θ) = 9.8 m/s² × 4 s = 39.2 m/s

$\therefore \dfrac{2 \cdot u \cdot sin(\theta)}{u \cdot cos(\theta)} = 2 \cdot tan(\theta) = \dfrac{39.2 \ m/s}{25 \ m/s} = 1.568$

tan(θ) = 1.568/2 = 0.784

θ = arctan(0.784) ≈ 38.096°

The direction of the velocity vector of the ball, θ ≈ 38.096°

From equation (1), we have;

u × cos(θ) = 25 m/s

∴ u = 25 m/s/cos(θ) = 25 m/s/cos(arctan(0.784)) = 31.7672787629 m/s

The magnitude of the initial velocity vector, u = 31.7672787629 m/s

The vertical component of the initial velocity, $u_y$ = u × sin(θ)

∴ $u_y$ = 31.7672787629 × sin(arctan(0.784))

Therefore, the initial velocity vector of the ball is approximately, v = 31.767 m/s in a direction 38.096° above the horizontal, from which we have;

u = uₓ·i + $u_y$ ·j = 25·i + 19.6·j

$\underset{u}{\rightarrow}$ = 25·i + 19.6·j

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2 years ago

A 2.00 m long string is vibrated 5.00 times every second to create a standing wave with 2 antinodes.

Diano4ka-milaya [45]

1. .23
2. 4
3. 6

that is the answer i know bc i already took a test on that and made a 100, so this is the answer

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3 years ago