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riadik2000 [5.3K]
3 years ago
14

¿cuáles son las ventajas de un experimento científico?​

Chemistry
1 answer:
Ierofanga [76]3 years ago
7 0

Answer:

Explanation:

Hacer proyectos de ciencia ayuda a desarrollar el ingenio de un niño

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You wish to generate 1.00 L of a 0.0750 M NaCl solution by diluting a more concentrated solution. What volume (in mL) of a 0.275
miss Akunina [59]

Taking into account the definition of dilution, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

<h3>Initial volume</h3>

In this case, you know:

  • Ci= 0.275 M
  • Vi= ?
  • Cf= 0.0750 M
  • Vf= 1 L

Replacing in the definition of dilution:

0.275 M× Vi= 0.0750 M× 1 L

Solving:

Vi=(0.0750 M× 1 L)÷ 0.275 M

<u><em>Vi= 0.27272 L= 272.72 mL</em></u>

In summary, you need to use a volume of 272.72 mL of a 0.275 M NaCl solution.

Learn more about dilution:

brainly.com/question/6692004

brainly.com/question/16343005

brainly.com/question/24709069

#SPJ1

8 0
2 years ago
PLEASE ANSWER, I WILL GIVE BRAINLIEST AND THANKS!
zheka24 [161]

Answer:

Mass  = 8 g

Explanation:

Given data:

Mass of MgO formed  = 20 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

2Mg + O₂     →    2MgO

Number of moles of MgO:

Number of moles = mass/molar mass

Number of moles = 20 g/ 40 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of MgO and O₂ from balance chemical equation:

                     MgO         :            O₂

                        2            :            1

                      0.5          :        1/2×0.5 = 0.25 mol

Mass of oxygen required:

Mass = number of moles × molar mass

Molar mass of O₂  is 32 g/mol

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

4 0
3 years ago
The lifetime of a human is approximately 71 years. Which of the following is this number closest to? Remember the following conv
jarptica [38.1K]

2.2Giga

Explanation:

Given that the number of years = 71years

We need to convert this to seconds;

   60s = 1 min

    60 min = 1hr

   24hr = 1 day

   7 days = 1 week

    52 weeks = 1yr

 71 years x \frac{52weeks }{1yr}  x \frac{7 days}{1 week } x \frac{24hr}{ 1day }  x \frac{60min}{1hr} x \frac{60s}{1min}  = 2,232,921,600‬s

This value is 2.2 x 10⁹s  = 2.2Giga

learn more:

Conversion brainly.com/question/555814

#learnwithBrainly

7 0
3 years ago
Suppose you will determine the composition of the unknown substance that was collected at the scene of the crime. You are encour
maria [59]

Answer:

b   erergart

Explanation:

6 0
3 years ago
Define "Dielectric" and list the Dielectric Constant values for vacuum and water
CaHeK987 [17]

Answer:

The term dielectric makes reference to materials that are insulators (the charges in the material does not flow freely and for this reason an insulator material cannot conduce electricity). BUT if we applied this material in an electric field they can be polarized.

Dielectric Constant: It is also defined as a relative permittivity and it is the amount of charge required to produce one unit of electric flux( electric field in a surface)  in a given medium.

it is typically denoted as Epsilon (ε)

and its formula is: ε = ε(ω) /ε(0)

where:

ε(ω) = the frequency-dependent permittivity of the material

ε(0) = the dielectric constant value in vacuum

Dielectric Constant values:

  • For vacuum is always 1
  • for water depending on the temperature can be 87.9 at 0º C, 80.2 at 20º C and 55.5 at 100º C.

7 0
3 years ago
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