The spring of a toy car is wound by pushing the car

Physics

2 answers:

attashe74 [19]2 years ago

8 0

7.5 Joules is the amount of elastic potential energy stored in the car's spring during this process.

w=Fd

w=(15)(0.5)

w = 7.5

Zepler [3.9K]2 years ago

7 0

The elastic potential energy stored in the car's spring during the process is 3.75 J

<h3>Determination of the spring constant</h3>

From the question given above, the following data were obtained:

Force (F) = 15 N

Extention (e) = 0.5 m

Spring constant (K) =?

K = F/e

K = 15 / 0.5

K = 30 N/m

<h3>Determination of the potential energy</h3>

Spring constant (K) = 30 N/m

Extention (e) = 0.5 m

Potential energy (PE) =?

PE = ½Ke²

PE = ½ × 30 × 0.5²

PE = 15 × 0.25

PE = 3.75 J

Therefore, the elastic potential energy stored in the car's spring during the process is 3.75 J

Learn more about energy stored in spring:

brainly.com/question/4280346

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Explanation:

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