Answer:
0.0734 grams LiOH
Explanation:
The molarity formula looks like this:
Molarity (M) = moles / volume (L)
You are given the molarity and volume (in mL). Therefore, you can plug these values into the equation and solve for moles (after you convert from mL to L).
25 mL / 1,000 = 0.025 L
0.125 M = moles / 0.025 L
(0.125 M) x (0.025 L) = moles
0.003125 = moles
After using the molarity formula, we know that 0.003125 moles LiOH are needed to satisfy these conditions. Now, we can convert this to grams using the molar mass of LiOH. This can be determined using the values from the periodic table. Remember to write your conversion in a way that allows for the units to cancel out.
Molar Mass (LiOH) = 6.941 g/mol + 16.00 g/mol + 1.008 g/mol
Molar Mass (LiOH) = 23.499 g/mol
0.003125 moles 23.499 g
------------------------ x ------------------- = 0.0734 grams LiOH
1 mole
This is due to the hydroxyl group in the alcohol which is able to form hydrogen bonds with water molecules.
Answer is D All of the above
Answer: 1618.8g of Zinc
Explanation:
We begin by writing a balanced chemical equation for the reaction.
Zn (s) + H2SO4 (aq) ----------> ZnSO4 (aq) + H2 (g)
Atomic mass of Zinc is 65.4g/mol
Molecular mass of hydrogen gas is 2.02 g/mol
Looking at the balanced equation;
2.02g is produced by 65.4g of Zn
50g would be produced by 65.4÷ 2.02 x 50 = 1618.8g of Zinc