Answer:
A. The pressure denoted as Pa and Pb at the surfaces of A and B in the tube is
PA= Pgas
PB= Patmos
B. The second sketch
C. The gas pressure is
Pgas= Patmos+ rho.g(h2-h1)
= 1atm + rho.g (h2-h1)
Explanation:
Answer:
The additional trials needed is 48 trials
Explanation:
Given;
initial number of trials, n = 16 trials
the standard deviation, σ = 0.24 s
initial standard error, ε = 0.06 s
The standard error is given by;
To reduce the standard error to 0.03 s, let the additional number of trials = x
Therefore, the additional trials needed is 48 trials.
<span>Place a test charge in the middle. It is 2cm away from each charge.
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point.
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out.
THIS IS A TRICK QUESTION.
THe electric field exactly midway between them = 0/Q = 0.
But if the point moves even slightly you need the following formula
F= (1/4Piε)(Q1Q2/D^2)
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
Answer:
a = change in v / change in time
= (5.2 - 11) / 3.1
= -1.87 m/s^2
Explanation:
