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dezoksy [38]
3 years ago
15

On a weather map, lines joining places with the same air pressure are called ___?

Physics
2 answers:
Svetlanka [38]3 years ago
6 0

Answer:

They are Isobars

Damm [24]3 years ago
4 0

Answer:

Isobars are lines on a weather map joining together places of equal atmospheric pressure. On the map the isobar marked 1004 represents an area of high pressure, while the isobar marked 976 represents an area of low pressure. Isobars on a weather map The numbers measure the atmospheric pressure in millibars.

Explanation:

Answer from: www.bbc.co.uk/bitesize/guides/z8yp7hv/revision/2

This is the exact answer so I advise that you do not copy and paste it or you might get in trouble.

Hope it helps bai!

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Answer:

<em><u>1)A)</u></em>

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4 0
3 years ago
A 2.00 kg ball is thrown upward at some unknown angle from the top of a 20.0 m high building. If the initial magnitude of the ve
Charra [1.4K]

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Explanation:

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3 years ago
Light can travel from the sun to ________ in less than ten minutes.
Solnce55 [7]
To the Earth in less than ten minutes. 
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3 years ago
In an inkjet printer, letters and images are created by squirting drops of ink horizontally at a sheet of paper from a rapidly m
Serga [27]

Answer:

q = 6.48 \times 10^{-14} C

Explanation:

Deflection in the drop is due to electric field force

so we will have

F = qE

acceleration of the drop is given as

a = \frac{qE}{m}

a = \frac{q(7.75 \times 10^4)}{1.00 \times 10^{-11}}

a = 7.75 \times 10^{15} q

now we know that time to cross the plates is given as

t = \frac{D}{v}

t = \frac{0.02}{18}

t = 1.11 \times 10^{-3} s

now the deflection is given as

d = \frac{1}{2}at^2

0.310 \times 10^{-3} = \frac{1}{2}(7.75 \times 10^{15} q)(1.11 \times 10^{-3})^2

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5 0
3 years ago
A brick in the shape of a cube with sides 10 cm has a density of 2500 kg/m^3. What is its weight? a.) 250 N
Arisa [49]

Answer:

c.) 25 N

Explanation:

 We find the volume of the brick, knowing that the volume of a cube is given by the formula:

l=0,1 metros \\V=l^{3}\\V=(0,1\: \: m)^{3}=0,001\: \: m^{3}

being l the side of the cube, which in this case is 10 cm or 0,1 m. Now we find the mass of the object, knowing the density and the Volume of the cube:

m=V*d\\m=(0,001 \:\:m^{3})(2500 \: \: \frac{Kg}{m^{3}})=2,5 \:\: Kg

We find the weight by multiplying the mass of the object with the gravity constant.

W=m*g=(2.5 \:Kg)*(9,81 \:m/s^{2} )=24,5 N\approx25\: N

8 0
3 years ago
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