The star that would be hotter would be; the star emitting visible light.
I can't help if u don't write the full question
Answer:
it's acceleration points tangentially to its trajectory in the direction of its motion at the top.
cause only it's horizontal velocity acts at the top. and it will be horizontal in the direction of it's motion.
Answer:
a) the total circle of "initial" is Epot./Eel. and the total circle of "final" is Ekin.
b)intia: 0.5 * 50 * 4^2 = 400 J
final: 0 J = 0.5 * 50 * 0^2
Explanation:
c) in the initial phase the spring is compressed and so has Epot but then the Energie changes to be totally Ekin (in final phase) and so the Epot becomes 0
