The anserr is c that what i think
Answer:
1.99 x 10⁻¹⁸J
Explanation:
Given parameters:
Frequency of the wave = 3 x 10¹⁵Hz
Unknown:
Energy of the photon = ?
Solution:
To solve this problem, we use the expression below;
E = hf
Where E is the energy, h is the Planck's constant and f is the frequency
Now insert the parameters and solve for E;
E = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J
Answer:
the brain and the spinal cord are the two main parts.
Answer: The value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.
Explanation:
Given: Moles of solute = 0.793 mol
Mass of solvent = 0.758

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Now, the values of
is calculated as follows.

where,
i = Van't Hoff factor = 1 (for chloroform)
m = molality
= molal boiling point elevation constant
Substitute the values into above formula as follows.

Thus, we can conclude that the value of
for chloroform is
when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.