Remember that density refers to the "mass per unit volume" of an object.
So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.
In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is
As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:
density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml
The effect on density would be that it would erroneously appear to be greater
Hope this helps!
Good luck
Complete Question
The complete question is shown on the first uploaded image
Answer:
10a The interest payment on the bond is = $ 8,204
10b The debit to cash for the bond proceeds is = $ 302,000
Explanation:
The explanation is shown on the second uploaded image
Answer:
Diasteriomers
Stereoisomers
Stereoisomers
Meso compounds
Constitutional isomers
Enantiomers
Enantiomers
Explanation:
Isomers are compounds that posses the same molecular formula but different structural formulas.
Constitutional isomers differ only in atom to atom connectivity while stereoisomers differ in arrangement of atoms in space. Stereo isomers differ in physical and chemical properties of the compounds.
When stereo isomers are non-superimpossible mirror images of each other, they are called enantiomers. Enantiomers have the same chemical and physical properties and differ only in their reaction with chiral substances.
Achiral compounds are compounds that do not exhibit chirality. Some achiral compounds contain stereogenic centers and are called meso compounds.
Answer: 94.13 L
Explanation: In STP in an ideal gas there is a standard value for both temperature and pressure. At STP,pressure is equal to 1atm and the temperature at 0°C is equal to 273.15K. This problem is an ideal gas so we use PV=nRT where R is a constant R= 0.08205 L.atm/mol.K.
To find volume, derive the equation, it becomes V=nRT/P. Substitute the values. V= 4.20 mol( 0.08205L.atm/mol.K)(273.15K) / 1 atm = 94.13 L. The mole units, atm and K will be cancelled out and L will be the remaining unit which is for volume.
night vision glasses detect energy
