Answer:
I'm sure its transverse, longitudinal and surface
Explanation:
sorry if I'm wrong
Answer:
The angular acceleration of the wheel is -6.54 rad/s²
Explanation:
We'll use the equations of motion for this.
w = 2πf
f = 75 rpm = 1.25 rps = 1.25 rev/s
w₀ = initial angular velocity = 2π × 1.25 = 7.85 rad/s
w = final angular velocity = 0 rad/s
t = 1.2 s
α = ?
w = w₀ + αt
0 = 7.85 + 1.2α
α = 7.85/1.2 = - 6.54 rad/s²
Answer:
moment of inertia I ≈ 4.0 x 10⁻³ kg.m²
Explanation:
given
point masses = 50g = 0.050kg
note: m₁=m₂=m₃=m₄=50g = 0.050kg
distance, r, from masses to eachother = 20cm = 0.20m
the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by
= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m
moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center
mathematically,
I = ∑m×d²
remember, a square will have 4 equal points
I = ∑m×d² = 4(m×d²)
I = 4 × 0.050 × (14.12 x 10⁻² m)²
I = 0.20 × 1.96 × 10⁻²
I = 3.92 x 10⁻³ kg.m²
I ≈ 4.0 x 10⁻³ kg.m²
attached is the diagram of the equation
Answer:
I₁/I₂ = 1000
Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.
Explanation:
First, we need to calculate the intensity of both the sounds. The formula for sound level is given as:
L = 10 log[I/I₀]
where,
L = Sound Level in dB
I = Intensity of sound
I₀ = Reference intensity = 10⁻¹² W/m²
<u>FOR SOUND OF SIREN:</u>
L = 120 dB
I = I₁ = ?
Therefore,
120 = 10 log[I₁/10⁻¹²]
log[I₁/10⁻¹²] = (120)/10
log[I₁/10⁻¹²] = 12
I₁/10⁻¹² = 10¹²
I₁ = (10¹²)(10⁻¹²)
I₁ = 1
<u>FOR SOUND OF WOLF'S HOWL:</u>
L = 90 dB
I = I₂ = ?
Therefore,
90 = 10 log[I₂/10⁻¹²]
log[I₂/10⁻¹²] = (90)/10
log[I₂/10⁻¹²] = 9
I₂/10⁻¹² = 10⁹
I₂ = (10⁹)(10⁻¹²)
I₂ = 10⁻³
Now, we divide the intensities:
I₁/I₂ = 1/10⁻³
I₁/I₂ = 10³
<u>I₁/I₂ = 1000</u>
<u>Thus, the sound of siren is 1000 times louder than the sound of wolf's howl.</u>
