The average distance between Earth and its moon is 384,000,000 meters. Express this distance in kilometers.

A pressure of 10 MPa is applied to 0.25m3 of a liquid, causing a volume reduction of 0.005 cm3. Determine the bulk modulus of el

Marina86 [1]

Answer:

K = 500 x 10⁶ MPa

Explanation:

Given that

P = 10 MPa

V= 0.25 m ³

Reduction in the volume ,ΔV=- 0.005 cm³

We know that 1 m = 1000 cm

ΔV=- 0.005 cm³ = - 0.005 x 10⁻⁶ m³

We know that bulk modulus given as

$K=-\dfrac{P}{\dfrac{\Delta V}{V}}$

Now by putting the values

$K=-\dfrac{10}{\dfrac{-0.005\times 10^{-6}}{0.25}}$

We get

K = 500 x 10⁶ MPa

Therefore the bulk modulus of the elasticity will be 500 x 10⁶ MPa.

6 0

3 years ago

A 1 kg object can be accelerated at 10 m/s^2. If you apply this same force to a 4kg object, what will its acceleration be?

AleksAgata [21]

Answer:

$a2 = 2.5~m/s^2$

Explanation:

<u>Mechanical Force</u>

According to the second Newton's law, the net force F exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object.

Assume we apply some given force F to an object of m1=1 Kg that produces an acceleration $a1=10 m/s^2$ , then:

F = m1.a1

The same force F is now applied to a second object m2=4 Kg that produces an acceleration a2, then:

F = m2.a2

Dividing both equations:

$\displaystyle 1=\frac{m1.a1}{m2.a2}$

Solving for a2:

$\displaystyle a2=\frac{m1.a1}{m2}$

Substituting values:

$\displaystyle a2=\frac{1*10}{4}$

$a2 = 2.5~m/s^2$

7 0

3 years ago

Question 3 (5 points)

Elan Coil [88]

True: when there is an angle between force and displacement, $W=Fd cos \theta$

Explanation:

The work done by a force when pushing/pulling an object is given by the equation

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

We have two extreme cases:

- When the force is parallel to the displacement, then $\theta=0^{\circ}$ and $cos \theta = 1$ , so the work done is maximum and simply becomes

$W=Fd$

- When the force is perpendicular to the displacement, then $\theta=90^{\circ}$ and $cos \theta =0$ , so the work done is zero.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0

3 years ago

Explain when acceleration remains constant.

stellarik [79]

Explanation:

acceleration remains constant when velocity does not increase or decrease

6 0

3 years ago

Tether ball is a game children play in which a ball hangs from a rope attached to the top of a tall pole. The children hit the b

Murljashka [212]

Answer:

a_total = 14.022 m/s²

Explanation:

The total acceleration of a uniform circular motion is given by the following formula:

$a=\sqrt{a_c^2+a_T^2}$ (1)

ac: centripetal acceleration

aT: tangential acceleration

Then, you first calculate the centripetal acceleration by using the following formula:

$a_c=r\omega^2$

r: radius of the circular trajectory = 2.0m

w: final angular velocity of the ball = 7.0 rad/s

$a_c=(2.0m)(7.0rad/s)^2=14.0\frac{m}{s^2}$

Next, you calculate the tangential acceleration. aT is calculate by using:

$a_T=r\alpha$ (2)

α: angular acceleration

The angular acceleration is:

$\alpha=\frac{\omega_o-\omega}{t}$

wo: initial angular velocity = 13 rad/s

t: time = 15 s

Then, you use the expression for the angular acceleration in the equation (1) and solve for aT:

$a_T=r(\frac{\omega_o-\omega}{t})=(2.0m)(\frac{7.0rad/s-13.0rad/s}{15s})=-0.8\frac{m}{s^2}$

Finally, you replace the values of aT and ac in the equation (1), in order to calculate the total acceleration:

$a=\sqrt{(14.0m/s^2)^2+(-0.8m/^2)^2}=14.022\frac{m}{s^2}$

The total acceleration of the ball is 14.022 m/s²

5 0

3 years ago