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2 years ago

4. Which statement correctly explains why hydrogen fluoride dissolves in water?

1 answer:

3 0

The ANSWER is D

salt In water because it is a simple ion pair Na+1 and Cl-1

Hydrogen Fluoride is similar: H+1 and F-1 and since it is a polar ion pair too it dissolves in water

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Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

Answer: The value of equilibrium constant for the reaction is 2448.1

Explanation:

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

4 0

3 years ago

SOMEONE PLEASE HELP

Snowcat [4.5K]

Answer:

a. release of heat flames or light - Physical Change

b. formation of precipitate - Chemical Change

c. change in substances size - Physical Change

d. change in an objects shape - Physical Change

e. change in an objects phase of matter - Physical Change

f. releasing gases/bubbles - Chemical Change

Explanation:

These are all either changes in physicality or in chemical structures; hope I helped either way!

6 0

2 years ago

Electrons found in the outer shell (or energy level) of an atom are called __________ electrons.

dimaraw [331]

The answer is c valence

3 0

3 years ago

If a 1.85 g mass of zinc produces 475 mL of gas and your balloon weighs 0.590 g and the room temperature is 23.5°C. Calculate th

ser-zykov [4K]

I came up with a required balloon volume of 476 before adding the extra 1 mL.

3 0

3 years ago

What mass of nitrogen monoxide is formed in the reaction of 869kg ammonia and 2480kg oxygen gas? (Please show work)

USPshnik [31]

Answer:

1533.6 kg NO

Explanation:

The reaction that takes place is:

4NH₃ + 5O₂ → 4NO + 6H₂O

First we convert the masses of ammonia (NH₃) and oxygen gas (O₂) into moles, using their respective molar masses:

NH₃ ⇒ 869 kg ÷ 17 kg/kmol = 51.12 kmol NH₃

O₂ ⇒ 2480 kg ÷ 32 kg/kmol = 77.5 kmol O₂

77.5 kmol of O₂ would react completely with (77.5 kmol O₂ * $\frac{4kmolNH_3}{5kmolO_2}$ ) 62 kmol of NH₃. There are not as many kmol of NH₃, so NH₃ is the limiting reactant.

Now we calculate how many kmol of NO are produced, using the limiting reactant moles:

51.12 kmol NH₃ * $\frac{4kmolNO}{4kmolNH_3}$ = 51.12 kmol NO

Finally we convert kmol of NO to mass, using its molar mass:

51.12 kmol NO * 30 kg/kmol = 1533.6 kg NO

6 0

2 years ago