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3 years ago

Was Wegener able to provide a mechanism as to how the plates moved accordingly? Why or why not?

Physics

1 answer:

Marina86 [1]3 years ago

3 0

Answer:

The main issue with Wegener's Continental Drift Theory was he did not have a mechanism behind the drifting of continents. He had a substantial amount of evidence that made sense; nonetheless, without a driving force behind it, the scientific community simply discredited his entire idea.

Explanation:

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A plane traveling horizontally at 120 m/s over flat ground at an elevation of 3610 m must drop an emergency packet on a target

allsm [11]

Answer:

Explanation:

Horizontal displacement

x = 120 t

Vertical position

y = 3610 - 4.9 t²

y = 0 for the ground

0 = 3610 - 4.9 t²

t = 27.14 s

This is the time it will take to reach the ground .

During this period , horizontal displacement

x = 120 x 27.14 m

= 3256.8 m

So packet should be released 3256.8 m before the target.

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3 years ago

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A ball is thrown straight upward on the Moon. Is the maximum height it reaches less than, equal to, or greater than the maximum

IgorC [24]

The maximum height on moon is HIGHER than the maximum height on earth

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3 years ago

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____ crust forms the ocean floors

Fittoniya [83]

Answer:

lithosphere

Explanation:

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3 years ago

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Which phrase best describes the side of the moon that faces Earth?

Artemon [7]

Answer:

I dont see any phrases to go with the answer was there any?

Explanation:

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2 years ago

A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free e

Serhud [2]

Answer: The electron number density (the number of electrons per unit volume) in the wire is $6.0 \times 10^{28} m^{-3}$ .

Explanation:

Given: Current = 5.0 A

Area = $4.0 \times 10^{-6} m^{2}$

Density = 2.7 $g/cm^{3}$ , Molar mass = 27 g

The electron density is calculated as follows.

$n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\$

where,

$\rho$ = density

M = molar mass

$N_{A}$ = Avogadro's number

Substitute the values into above formula as follows.

$n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}$

Thus, we can conclude that the electron number density (the number of electrons per unit volume) in the wire is $6.0 \times 10^{28} m^{-3}$ .

8 0

2 years ago