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Alex
2 years ago
7

Một đoạn mạch gồm R1=8 ôm;R2=12 ôm.biết R1 nối tiếp với đoạn mạch gồm R2 song song với R3; R3=1/2 R2 cường độ dòng điện chạy qua

mặt chính là 2A
a. Hãy vẽ sơ đồ mạch điện trên
b. Tính điện trở tương đương toàn mạch
c. tính cường độ dòng điện qua mỗi điện trở
Physics
1 answer:
LUCKY_DIMON [66]2 years ago
7 0

Answer:

Explanation:

a.

b. R3= 1/2R2=6 ôm

R12= R1+R2=20 ôm

Rtđ=R12.R3/R12+R3= 4,62 ôm

c. U= I.Rtđ = 2.4,62=9,23 V

I1=I2= 9,23/20= 0,4615 A

I3= 2-0,4615=1,5385 A

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Answer:

Free electrons

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When doing numerical calculations involving temperature, you need to pay particular attention to the temperature scale you are u
Mrac [35]

1) 293 ^{\circ}C

2) 859^{\circ}C

Explanation:

1)

The average kinetic energy of the molecules of an ideal gas is directly related to the Kelvin temperature of the gas, by the formula

KE=\frac{3}{2}kT

where

KE is the kinetic energy

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T is the Kelvin temperature

We can say  therefore that the average kinetic energy of the particles is directly proportional to the absolute temperature of the gas; so, we can write:

KE\propto T

And therefore

\frac{KE_1}{KE_2}=\frac{T_1}{T_2} (1)

In this problem, we have:

KE_1 = K_{10} is the initial kinetic energy of the molecules when the temperature of the gas is

T_1=10^{\circ}+273=283 K

Here we want to find the temperature T_2 at which the average kinetic energy of the particles is

KE_2=2K_{10}

So, twice the initial value. Substituting into eq.(1) and solving for T2, we find:

T_2=\frac{T_1 KE_2}{KE_1}=\frac{(283)(2K_{10})}{K_{10}}=566 K

Converting into Celsius degrees,

T_2=566-273=293 ^{\circ}C

2)

The root-mean-square (rms) speed of the molecules in a gas is given by the equation

v=\sqrt{\frac{3kT}{m}}

where

k is the Boltzmann constant

T is the Kelvin temperature of the gas

m is the mass of each molecule

Therefore, from the equation we can say that the rms speed is proportional to the square root of the temperature:

v\propto \sqrt{T}

So we can write:

\frac{v_1}{v_2}=\frac{\sqrt{T_1}}{\sqrt{T_2}} (2)

where in this problem:

v_1 = v_{rms} is the rms speed of the molecules when the temperature is

T_1=10^{\circ}C+273=283 K

v_2=2v_{rms} is the final rms speed of the molecules

Solving eq.(2), we find the temperature at which the rms speed is twice the initial value:

T_2=T_1 (\frac{v_2}{v_1})^2=(283)(\frac{2v_{rms}}{v_{rms}})^2=1132 K

Converting into Celsius degrees,

T_2=1132-273=859^{\circ}C

8 0
3 years ago
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Answer:

1. It may change the direction of an object in motion.

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Explanation:

1.It may change the direction of an object in motion.

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For example, a sailboat moving eastward, can suddenly change its direction by interaction of a storm wind blowing form the south.

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