Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject
Explanation: so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³ so all we have to do is to find the molecular relative mass(mr) .
to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.
NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass
now we fix it in our formulae which is m=n× mr
m=1.5× 40 =60 so our mass is 60grams or 60g
HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment
The answer cl atoms are in zn(cio3)2 is A:2 because I looked it up and it gave me 2.
Answer:
Fewer bubbles will be produced because of fewer collisions of reactant molecules
Explanation:
As the solid dissolves into the solution after the liquid has been vigorously bubbled, if the temperature of the liquid is reduced a little, what will happen is that fewer bubbles will be produced as a result of lesser amount of collisions occurring between the reactant molecules
Answer:
The value of dissociation constant of the monoprotic acid is 
.
Explanation:
The pH of the solution = 2.46
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
![2.46=-\log[H^+]](https://tex.z-dn.net/?f=2.46%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=0.003467 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.003467%20M)
Initially
0.0144 0 0
At equilibrium
(0.0144-x) x x
The expression if an dissociation constant is given by :
![K_a=\frac{[A^-][H^+]}{[HA]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BA%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHA%5D%7D)
![x=[H^+]=0.003467 M](https://tex.z-dn.net/?f=x%3D%5BH%5E%2B%5D%3D0.003467%20M)
The value of dissociation constant of the monoprotic acid is .
Answer:
52
Explanation:
This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG
