Answer:
a) 5
b) 4
c) 3
d) 3
e) 4
Explanation:
I use only one rule when the decimal is present, meaning you can see the decimal (as is the case with all of these).
When the decimal is Present, start counting sig figs from the Pacific (left) side of the number beginning with the first non-zero digit and count all the way to the end.
So, for example, in "a", the first non-zero digit starting from the left is 1, then continue counting all the way to the right side.
For "c", the first non-zero digit is the left most 4 (skip the first 4 zeros), then count all the way to the right side.
O
Explanation:
Oxygen is a more reactive non-metal.
There are several parameters to test how reactive an element is. In this case, we are going to use the electronegativity of the two atoms.
- Electronegativity is the relative tendency with which atoms of the element attract valence electrons in a chemical bond.
A high electronegativity value suggests more reactivity and a low value implies low reactivity.
On the Pauling's Eelectronegativity table, Oxygen has a value of 3.5 and Phosphorus has 2.1
It implies that oxygen is a more reactive non-metal compared to phosphorus.
Learn more:
Electronegativity brainly.com/question/11932624
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The structure of alkene is given below in the image.
Alkenes are described as both branched or unbranched hydrocarbons that possess at least one carbon-carbon double bond (CC) and feature a popular system of CnH2n [1].
Alkanes are organic compounds that encompass single-bonded carbon and hydrogen atoms. The formulation for Alkanes is CnH2n+2, subdivided into 3 companies – chain alkanes, cycloalkanes, and branched alkanes.
The geometry around each carbon atom is based totally on a trigonal planar shape, due to the fact, that each carbon has three electrons around it. This must make the angle of each bond one hundred twenty.
Learn more about Alkanes here: brainly.com/question/17040500
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Answer:
The value of
at 4224 K is 314.23.
Explanation:

Initially
4.97 atm 0
At equilibrium
4.97 - p 2p
At initial stage, the partial pressure of oxygen gas = =4.97 atm
At equilibrium, the partial pressure of oxygen gas = 
So, 4.97 - p = 0.28 atm
p = 4.69 atm
At equilibrium, the partial pressure of O gas = 
The expression of
is given as :


The value of
at 4224 K is 314.23.