Given :
A 120 kg box is on the verge of slipping down an inclined plane with an angle of inclination of 47º.
To Find :
The coefficient of static friction between the box and the plane.
Solution :
Vertical component of force :
Horizontal component of force(Normal reaction) :
Since, box is on the verge of slipping :
Therefore, the coefficient of static friction between the box and the plane is 1.07.
Hence, this is the required solution.
Power output = V*I=11000*750=8250 kVA= 8250 kW
Answer:
Explanation: societal law is A statement about how things act in the natural world. the wire and electro magnet need to touch in question 2. a decrease in spee decreases kinetic energy. the test variable was the distance traveled by the scrunched paper.
The electric field of a charged object will be strongest when all the field lines are close to one another.
beacsue, the strength of electric field depends on the number of lines of electric field. More lines at a place, higher the electric field strength. Thus, any charge in that area will face more electric field.
Hooke's law states that for a helical spring the extension is directly proportional to the force applied provided the elastic limit is not exceeded.
Therefore; F= ke, where k is the spring constant, F is the force and e is the extension.
k = 2700 N/m and e = 3 cm or 0.03 M
therefore, F = 2700 × 0.03
= 81 N
Thus, the force required will be 81 N
