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Gennadij [26K]
3 years ago
8

Describe the role of capacitors in the circuit in 2 sentences

Physics
2 answers:
sergeinik [125]3 years ago
8 0

Answer:

A capacitor is an electronic component that stores and releases electricity in a circuit. It also passes alternating current without passing direct current. A capacitor is an indispensible part of electronic equipment and is thus almost invariably used in an electronic circuit.

olga nikolaevna [1]3 years ago
4 0

Capacitors are useful to reduce the voltage pulsation. When the high voltage is applied to the parallel circuit, the capacitor is charged, and on the other hand, it is discharged with the low voltage. While electricity flowing out is alternating current, most of electronic circuits work with direct current.

mark me brainliesttt :))

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A mad scientist wants to collect massive amounts of charge on basketball sized aluminum balls. The scientist wants to place 6 C
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The distance between two basket ball sized aluminium balls is 9714 m.

Explanation:

Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force .

Coulomb's law formula => F = (k * Qb1 * Qb2)/r²

Given data :-

charge on ball 1 Qb1 = 6C

charge on ball 2 Qb2 = 14C

Force exerted F = 8000 N

k =  8.988 x 10^9 Nm²C−²(coulomb's constant).

substituting given values in the coulomb's formula

8000 = (( 8.988 x 10^9)*6*14)/r²

shifting r and 8000 to other sides

r² = (756 * 10^9)/8000

r = 9714 m.

Therefore the distance between two balls is r = 9714 m.

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3 years ago
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A man standing 1.54 m in front of a shaving mirror produces a real, inverted image 15.2 cm from it. What is the focal length of
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Answer:

The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

Explanation:

Given that,

Object distance u=1.54 m =154 cm

Image distance v = 15.2 cm

Magnification = 2

We need to calculate the focal length

Using formula of mirror

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{f}=\dfrac{1}{15.2}+\dfrac{1}{-154}

\dfrac{1}{f}=\dfrac{347}{5852}

f=16.86\ cm

We need to calculate the focal length

Using formula of magnification

m= \dfrac{-v}{u}

Put the value into the formula

2=\dfrac{v}{u}

v = -2u

Using formula of for focal length

\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}

\dfrac{1}{16.86}=\dfrac{1}{u}-\dfrac{1}{2u}

\dfrac{1}{16.86}=\dfrac{1}{2u}

2u=16.86

u=\dfrac{16.86}{2}

u=8.43\ cm

Hence, The focal length is 16.86 cm and the distance of the man  if he wants to form an upright image of his chin that is twice the chin's actual size is 8.43 cm.

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