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Ainat [17]
2 years ago
6

Find the mass of a person who weighs 608 N

Physics
2 answers:
Verdich [7]2 years ago
8 0

weight = mass × accelaration due to gravity

608 = x × 10

x= 608 ÷ 10 = 60.8

mass = 60.8

Anvisha [2.4K]2 years ago
7 0

Answer:

weight = mass \times accelaration \: due \: to \: gravity \\ 608 = x \times 10 \\ x = 608 \div 10 = 60.8 \\ mass = 60.8 \\ thank \: you

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Hey there,

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Light of frequency 2.5 x 1015 Hz illuminates a
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Answer:

h f = W + KE

Input energy equals work function plus KE of emitted electron

W = 6.63E-34 * 2.5E15 - 6.3 * 1.6E-19

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W = (16.6 - 10.1)E-19 = 6.5E-19 J

h f = 6.5E-19 J        for electrons to be emitted with zero KE

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2 years ago
10. Luther is designing a roller coaster for an amusement park. At one point, the roller coaster will enter a horizontal loop at
Charra [1.4K]

Answer:

centripital acceleration= v^2/r

r = v^2/a

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3 0
3 years ago
In physics, a field refers to a quantity that has a value for every point in a space. In a sense, a field is like a function in
enyata [817]

Answer:

Explanation:

a ) Temperature at ground level is a field and it is scalar field .At any point in space near ground level  , the temperature is specific so it is a field .  It is scalar  because temperature has no direction .

b )

 Wind velocity at 100 feet above the ground is also a field but it is a vector field . At any point in space , the wind velocity is specific so it is a field .  It is vector   because velocity  has a particular  direction at any point .

c )

Gravitational force on Roessler Hall is a vector field because gravitational force also depends on location in space and it has direction.

d )

Height of a person in your group is not a space because it does not depend upon  location is space . It is same for all location .

e )

Height (above sea level) of the ground is a field  because it also depends upon location in space . It is scalar field .

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3 0
3 years ago
In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.40×1016 kg and a ra
Arturiano [62]

A) 8.11 m/s

For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

m\frac{v^2}{(R+h)}=\frac{GMm}{(R+h)^2}

where

m is the satellite's mass

v is the speed

R is the radius of the asteroide

h is the altitude of the satellite

G is the gravitational constant

M is the mass of the asteroid

Solving the equation for v, we find

v=\sqrt{\frac{GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

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B) 11.47 m/s

The escape speed of an object from the surface of a planet/asteroid is given by

v=\sqrt{\frac{2GM}{R+h}}

where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}

M=1.40\cdot 10^{16}kg

R=8.20 km=8200 m

h=6.00 km = 6000 m

Substituting into the formula, we find:

v=\sqrt{\frac{2(6.67\cdot 10^{-11})(1.40\cdot 10^{16}kg)}{8200 m+6000 m}}=11.47 m/s

5 0
3 years ago
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