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Lesechka [4]
3 years ago
12

In the activation–synthesis model of dreaming, what is synthesized?

Physics
1 answer:
astra-53 [7]3 years ago
6 0

Answer:

hopefully that helps

Explanation:

B. a hodgepodge of memories and sensations that are internally generated by the brain

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A friend is telling you about a type of high-energy, short-wavelength electromagnetic wave. She is MOST LIKELY to be talking abo
Masteriza [31]

Answer: A. X-rays

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X-rays have the shortest wavelength and the highest energy of all of the options given.

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How does the observed pitch of the buzzer change as it moves
andriy [413]

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Pitch of the buzzer increased (higher tone) as it moves towards the observer

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astra-53 [7]

Answer:

D. provide the most compelling evidence of cause-and-effect relationships.

Explanation:

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3 years ago
A man has a mass of 66 kg on the earth. What is his weight.
LUCKY_DIMON [66]
Since force = mass X acceleration, then the force he excerts on the earth (aka his weight) equals his mass times the force of gravity.

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8 0
3 years ago
For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ
slava [35]

Explanation:

First we will convert the given mass from lb to kg as follows.

        157 lb = 157 lb \times \frac{1 kg}{2.2046 lb}

                   = 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

         180 \frac{mg}{kg} \times 71.215 kg

         = 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

      0.65% (w/w) = \frac{0.65 g}{100 g}

                           = \frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}

                           = \frac{0.65 g}{100 ml}

Therefore, calculate the volume which contains the amount of caffeine as follows.

   12818.7 mg = 12.8187 g = \frac{12.8187 g}{\frac{0.65 g}{100 ml}}

                       = 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

5 0
3 years ago
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