The best name for the ionic bond that forms between them is Beryllium Bromide.
We have been provided with data,
Beryllium charge, q = 2
Bromine charge, q = -1
As we know the valance electron of Be is +2 and the valance electron of bromine is -1. Since one is metallic and the other is non-metallic.
Now, when they combine they exchange valance electron, and bromine change into bromide so they form Beryllium Bromide.
So, the best name for the ionic bond that forms between them is Beryllium Bromide.
Learn more about ionic bonds here:
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Biceps curls & pushups , benchpress
Answer:
1.195 m
2.8375 s
2.21433 rad/s
Explanation:
d = Distance = 2.39 m
N = Number of cycles = 8
t = Time to complete 8 cycles = 22.7 s
Radius would be equal to the distance divided by 2
![r=\frac{d}{2}\\\Rightarrow r=\frac{2.39}{2}\\\Rightarrow r=1.195\ m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%5C%5C%5CRightarrow%20r%3D%5Cfrac%7B2.39%7D%7B2%7D%5C%5C%5CRightarrow%20r%3D1.195%5C%20m)
The radius is 1.195 m
Time period would be given by
![T=\frac{t}{N}\\\Rightarrow T=\frac{22.7}{8}\\\Rightarrow T=2.8375\ s](https://tex.z-dn.net/?f=T%3D%5Cfrac%7Bt%7D%7BN%7D%5C%5C%5CRightarrow%20T%3D%5Cfrac%7B22.7%7D%7B8%7D%5C%5C%5CRightarrow%20T%3D2.8375%5C%20s)
Time period of the motion is 2.8375 s
Angular speed is given by
![\omega=\frac{2\pi}{T}\\\Rightarrow \omega=\frac{2\pi}{2.8375}\\\Rightarrow \omega=2.21433\ rad/s](https://tex.z-dn.net/?f=%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7BT%7D%5C%5C%5CRightarrow%20%5Comega%3D%5Cfrac%7B2%5Cpi%7D%7B2.8375%7D%5C%5C%5CRightarrow%20%5Comega%3D2.21433%5C%20rad%2Fs)
The angular speed of the motion is 2.21433 rad/s
Answer: Jupiter's mass
Explanation:
From Kepler's third law:
![T^2=\frac{4\pi^2}{GM}a^3](https://tex.z-dn.net/?f=T%5E2%3D%5Cfrac%7B4%5Cpi%5E2%7D%7BGM%7Da%5E3)
where T is the orbital period of a satellite, a is the average distance of the satellite from the Planet, M is the mass of the planet, G is the gravitational constant.
If the average distance of one of Jupiter's moons to Jupiter and its orbital period around Jupiter is given then mass of the Jupiter can be found:
![\Rightarrow M_J=\frac{4\pi^2}{GT_m^2}a_m^3](https://tex.z-dn.net/?f=%5CRightarrow%20M_J%3D%5Cfrac%7B4%5Cpi%5E2%7D%7BGT_m%5E2%7Da_m%5E3)