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Veronika [31]
3 years ago
8

Patrick Mahomes is throwing a football with an applied force of 230 N but is experiencing air resistance of 30 N. The ball has a

mass of 5kg. What is the acceleration of the ball?
Physics
1 answer:
Ganezh [65]3 years ago
7 0

Answer:

www.chiefs.com

Web results

Patrick Mahomes

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Which groups on the periodic table contain metalloids?
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Metalloids are in Group 13 to 16
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What is the oscillation period of your eardrum when you are listening to the A4 note on a piano (frequency 440 Hz)?
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The period is the inverse of the frequence:

T=\dfrac{1}{f}=\dfrac{1}{440}=0.0022\overline{72}

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HELP ME <br> the bending of light when it changes media is called _________<br> u can get brainliest
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Answer:

Refraction

Explanation:

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A bicyclist of mass 112 kg rides in a circle at a speed of 8.9 m/s. If the radius of the circle is 15.5 m, what is the centripet
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The centripetal force, Fc, is calculated through the equation, 
                                    Fc = mv²/r
where m is the mass,v is the velocity, and r is the radius. 
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                                     Fc = (112 kg)(8.9 m/s)² / (15.5 m)
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Therefore, the centripetal force of the bicyclist is approximately 572.36 N. 
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Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example
iragen [17]

Given Information:

Magnetic field = B = 1×10⁻³ T

Frequency = f = 72.5 Hz

Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m

Required Information:

Maximum Emf = ?

Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

Emf = BAωcos(ωt)

Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

Emf = BAω

Area is given by

A = πr²

A = π(d/2)²

A = π(7.60×10⁻⁶/2)²

A = 45.36×10⁻¹² m²

We know that,

ω = 2πf

ω = 2π(72.5)

ω = 455.53 rad/sec

Finally, the emf is,

Emf = BAω

Emf = 1×10⁻³*45.36×10⁻¹²*455.53

Emf = 20.66×10⁻¹² volts

Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts

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