Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
This can be seen the image attached.
The angle between phosphorous and chlorine is 90⁰C. As it has octahedral geometry.
So the answer is as follows:
Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
The angle between phosphorous and chlorine is 90⁰C.
<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.
<u>Explanation:</u>
For the given nuclear reaction:
We are given:
Mass of = 39.963998 u
Mass of = 39.962591 u
To calculate the mass defect, we use the equation:
Putting values in above equation, we get:
To calculate the energy released, we use the equation:
(Conversion factor:
)
Hence, the energy released in the given nuclear reaction is 1.3106 MeV.