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vekshin1
2 years ago
6

WHAT IS THE COLOR OF METHYL ORANGE 1. YELLOW2. PINK3. ORANGE​

Chemistry
2 answers:
Leya [2.2K]2 years ago
7 0

Answer:

3.Orange it literally say's it methyl ORANGE

Explanation:

Brainliest plz

hoa [83]2 years ago
5 0

Answer:

Other indicators

Indicator Acidic Alkaline

Methyl orange Red Yellow

Phenolphthalein Colourless Pink

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Why is burning wood a chemical change?
Nitella [24]
There are 4 things that are evidence of a chemical change.
1)Change in color
2)Change in shape (gas being let out)
3)Change in temperature
4)Change in smell

Burning wood is a chemical change because it has a change in color, and shape.
3 0
3 years ago
What is the energy of an electron in the third energy level of hydrogen?
Roman55 [17]

Answer:

Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy.

...

Energy Levels of Electrons.

Energy Level Energy

1 -13.6 eV

2 -3.4 eV

3 -1.51 eV

4 -.85 eV

4 0
3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
A sample of gaseous neon atoms at atmospheric pressure and 0 °c contains 2.69 * 1022 atoms per liter. the atomic radius of neon
omeli [17]

Explanation

Radius of neon atom : 69 pm = 69\times 10^{-12} m

Volume occupied by the one atom:\frac{4}{3}\pi r^3

=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3

given that 2.69\times 10^{22} atoms are present in 1L

1 L = 0.001 m^3

The volume occupied by the 2.69\times 10^{22} neon atoms

2.69\times 10^{22}\times 1.37\times 10^{-30} m^3=3.68\times 10^{-8} m^3

Fraction of volume occupied by the neon atom:

=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3

3.68\times 10^{-11} m^3

The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

3 0
3 years ago
How many different elements are present in c6h12o6
Margarita [4]

Answer:

3 different elements are present in the compound.

5 0
2 years ago
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