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lisov135 [29]
3 years ago
6

In order to defend against side channel power analysis, we should: ______________

Engineering
1 answer:
wariber [46]2 years ago
8 0

Answer:

Some examples of predator and prey are lion and zebra, bear and fish, and fox and rabbit. ... The words "predator" and "prey" are almost always used to mean only animals that eat animals, but the same concept also applies to plants: Bear and berry, rabbit and lettuce, grasshopper and leaf

Explanation:

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On highways, the far left lane is usually the _____. A. emergency lane B. merge lane C. slowest D. fastest
slamgirl [31]

On highways, the far left lane is usually the<u> fastest</u> moving traffic.

Answer: Option D.

<u>Explanation:</u>

For the most part, the right lane of a freeway is for entering and leaving the traffic stream. It is an arranging path, for use toward the start and end of your interstate run. The center paths are for through traffic, and the left path is for passing. On the off chance that you are not passing somebody, try not to be driving in the left path.

Regular practice and most law on United States expressways is that the left path is saved for passing and quicker moving traffic, and that traffic utilizing the left path must respect traffic wishing to surpass.

7 0
3 years ago
Read 2 more answers
A 20-mm-diameter steel bar is to be used as a torsion spring. If the torsional stress in the bar is not to exceed 110 MPa when o
ch4aika [34]

Answer:

1.887 m

Explanation:

(15 *pi)/180

= 0.2618 rad

Polar moment

= Pi*d⁴/32

= (22/7*20⁴)/32

= 15707.96

Torque on shaft

= ((22/7)*20³*110)/16

= 172857.14

= 172.8nm

Shear modulus

G = 79.3

L = Gjθ/T

= 79.3x10⁹x(1.571*10^-8)x0.2618/172.8

= 1.887 m

The length of the bar is therefore 1.887 meters

5 0
3 years ago
Consider CO at 500 K and 1000 kPa at an initial state that expands to a final pressure of 200 kPa in an isentropic manner. Repor
REY [17]

Answer:

T_2=315.69k

Explanation:

Initial Temperature T_1=500K

Initial Pressure P_1=1000kPa

Final Pressure P_2=200kPa

Generally the gas equation is mathematically given by

\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{n-1}{n}}

Where

n for CO=1.4

Therefore

\frac{T_2}{500}=\frac{200}{1000}^{\frac{1.4-1}{1.4}}

T_2=315.69k

7 0
2 years ago
Refrigerant-134a at 700 kPa, 70°C, and 7.2 kg/min is cooled by water in a condenser until it exists as a saturated liquid at the
alex41 [277]

Answer:

The mass flow rate of cooling water required to cool the refrigerant is 123.788\,\frac{kg}{min}.

Explanation:

A condenser is a heat exchanger used to cool working fluid (Refrigerant 134a) at the expense of cooling fluid (water), which works usually at steady state. Let suppose that there is no heat interactions between condenser and surroundings.The condenser is modelled after the First Law of Thermodynamics, which states:

\dot Q_{ref} - \dot Q_{w} = 0

\dot Q_{ref} = \dot Q_{w}

\dot m_{ref}\cdot (h_{ref, in} - h_{ref,out}) = \dot m_{w}\cdot (h_{w, out} - h_{w,in})

The mass flow rate of the cooling water is now cleared:

\dot m_{w} = \dot m_{ref }\cdot \frac{h_{ref,in}-h_{ref,out}}{h_{w,out}-h_{w,in}}

Given that h_{ref,in} = 808.34\,\frac{kJ}{kg}, h_{ref, out} = 88.82\,\frac{kJ}{kg}, h_{w,out} = 104.83\,\frac{kJ}{kg} and h_{w,in} = 62.98\,\frac{kJ}{kg}, the mass flow of the cooling water is:

\dot m_{w} = \left(7.2\,\frac{kg}{min} \right)\cdot \left(\frac{808.34\,\frac{kJ}{kg}-88.82\,\frac{kJ}{kg} }{104.83\,\frac{kJ}{kg}-62.98\,\frac{kJ}{kg} } \right)

\dot m_{w} = 123.788\,\frac{kg}{min}

The mass flow rate of cooling water required to cool the refrigerant is 123.788\,\frac{kg}{min}.

4 0
3 years ago
Describe how gene therapy can be a social issue and give rise to moral, ethical and legal debates. Justify your response in two
den301095 [7]

Answer: stigmatism and discrimination

Explanation:

Knowledge of genetic risks can lead to potential social and psychological consequences for the individual. Socially, knowledge from genetic tests may lead to stigmatization and discrimination within the community.

8 0
3 years ago
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