Answer:
Photos are attached. Step wise solution is given.
1. Velocity of air at inlet is calculated.
2.Temperature of air at exit in Kelvin is also calculated.
3.Exit Cross-Sectional area
Best Regards.
Answer:
The correct option is;
Fluid power systems are much more efficient with regards to energy costs and overall cost savings
Explanation:
The option that will provide a valid reason for the larger proportion of the consumers to change to the fluid power trucks from the diesel powered trucks is the possibility of increased efficiency in the cost of energy, and the cost savings to be made from making the switch to the fluid power trucks, due to the lower input required and the faster rate at which the consumer budget will be rebalanced leading to increased return on investment and improved rate of return.
Answer:
n this question, we are asked to find the probability that
R1 is normally distributed with mean 65 and standard deviation 10
R2 is normally distributed with mean 75 and standard deviation 5
Both resistor are connected in series.
We need to find P(R2>R1)
the we can re write as,
P(R2>R1) = P(R2-R1>R1-R1)
P(R2>R1) = P(R2-R1>0)
P(R2>R1) = P(R>0)
Where;
R = R2 - R1
Since both and are independent random variable and normally distributed, we can do the linear combinations of mean and standard deviations.
u = u2-u1
u = 75 - 65 = 10ohm
sd = √sd1² + sd2²
sd = √10²+5²
sd = √100+25 = 11.18ohm
Now we will calculate the z-score, to find P( R>0 )
Z = ( X -u)/sd
the z score of 0 is
z = 0 - 10/11.18
z= - 0.89
Answer:
That's a high score!
This is a test question!
Explanation:
The reason these two lines are printed and not the first one is simple. After the 'IF' condition has been stated, there is no use of parenthesis such as { and } to enclose the next lines. This means that only the first line after the 'IF' condition may be read or skipped depending on whether the condition (score>95) is met. Since the score is not larger than 95, and the 'IF' condition fails, the line 'Congratulations!' is not printed. The next two lines of the code are read as normal because they do not depend on the 'IF' condition.
Answer:
with a square cross section and length L that can support an end load of F without yielding. You also wish to minimize the amount the beam deflects under load. What is the free variable(s) (other than the material) for this design problem?
a. End load, F.
b. Length, L.
c. Beam thickness, b
d. Deflection, δ
e. Answers b and c.
f. All of the above.
