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olga nikolaevna [1]
3 years ago
8

What is the acceleration of the box shown below.

Physics
2 answers:
-BARSIC- [3]3 years ago
4 0

Explanation:

Fnet= Fapp - F friction

=50-30

=20 N

Acceleration= force/ mass

=20/20

=1.0 m/s²

olga nikolaevna [1]3 years ago
3 0

Answer:

D) 1.0m/s^2

Explanation:

Force = 50 - 30 = 20

Acceleration = 20/20

= 1

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3 0
3 years ago
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MA_775_DIABLO [31]

Answer:

KE = 4217 J

Explanation:

As we know that the wheel is rotated at constant angular speed

so here we can say that the angular speed is given as

\omega = \frac{2\pi}{T}

\omega = \frac{2\pi}{2 \times 60}

\omega = 0.052 rad/s

now the moment of inertia of all passengers is given as

I = 36(60)(\frac{76}{2})^2

I = 3119040 kg m^2

now work done by machine must be equal to kinetic energy of the system

so we will have

KE = \frac{1}{2}I\omega^2

KE = \frac{1}{2}(3119040)(0.052)^2

KE = 4217 J

7 0
3 years ago
An object moving at 30 m/s takes 5s to come to a stop. what is the object's acceleration?
Taya2010 [7]
Use SUVAT where:
S = distance
U = initial velocity = 30m/s
V = end velocity = 0 m/s
A = acceleration = ?
T = time = 5 secs

then pick out the equation v = u + at

so:
0 = 30 + 5a
-30 / 5 = a
a = -6 m/s^2
4 0
3 years ago
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