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pogonyaev
3 years ago
6

What are the five plants you can see from earth without a telescope?

Physics
1 answer:
nevsk [136]3 years ago
3 0
The five planets that you can see from Earth without a telescope are Mercury, Venus, Mars, Jupiter and Saturn. 
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The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing
konstantin123 [22]

Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

5 0
2 years ago
The half life of uranium-235 is 4. 5 billion years. If 0. 5 half-lives have elapsed, how many years have gone by?
igor_vitrenko [27]

Answer:

2.25 billion years

Explanation:

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5 0
2 years ago
What sport is better for girls volleyball or softball?
kipiarov [429]
Either one is fun and great to play!
3 0
3 years ago
Read 2 more answers
A wad of clay of mass m1 = 0.49 kg with an initial horizontal velocity v1 = 1.89 m/s hits and adheres to the massless rigid bar
notka56 [123]

Answer:

<h2>The angular velocity just after collision is given as</h2><h2>\omega = 0.23 rad/s</h2><h2>At the time of collision the hinge point will exert net external force on it so linear momentum is not conserved</h2>

Explanation:

As per given figure we know that there is no external torque about hinge point on the system of given mass

So here we will have

L_i = L_f

now we can say

m_1v_1\frac{L}{2} = (m_2L^2 + m_1(\frac{L}{2})^2)\omega

so we will have

0.49(1.89)(0.45) = (2.13(0.90)^2 + 0.49(0.45)^2)\omega

\omega = 0.23 rad/s

Linear momentum of the system is not conserved because at the time of collision the hinge point will exert net external force on the system of mass

So we can use angular momentum conservation about the hinge point

6 0
3 years ago
what is the electric potential at point A in the electric field created by a point charge of 5.5 • 10^-12 C? estimate k as 9.00
Hitman42 [59]

The electric potential at point A in the electric field= 0.099 x 10 ⁻¹v

<u>Explanation</u>:

Given data,

charge = 5.5 x 10¹² C

k =9.00 x 10⁹

The electric potential V of a point charge can found by,

V= kQ / r

Assuming, r=5.00×10⁻² m

V= 5.5 x 10⁻¹²C x  9.00 x 10⁹ / 5.00×10⁻² m

V=  49.5 x 10⁻³/ 5.00×10⁻²

Electric potential V=  0.099 x 10⁻¹v

3 0
3 years ago
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