Answer:
The surface water features and storm water runoff within watershed ultimately drain to other bodies of water.
Explanation:
Divide 2500 g by 500 cc. The quotient is 5 g/cc ... the density.
Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated;
= 150 MW
Heat input;
= 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input;
- Net power generated; 
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s
Hydrogen makes stars and stars spend most of their lifetime making helium.
The heavier elements are made when an old-age, high mass star explodes as a nova or supernova and then dies.
Answer:
The final speed of the train car is 8.57 m/s.
Explanation:
Given that,
Mass of train car = 1000 kg
Mass of sand = 400 kg
Speed of train car = 12 m/s
We need to calculate the final speed of the train car after the sand is dumped
Using conservation of momentum
...(I)
Put the value in the equation (I)



Hence, The final speed of the train car is 8.57 m/s.