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Kruka [31]
3 years ago
5

A double star has two components of equal brightness, each with a magnitude of 8.34. if these stars are so close together that t

hey appear to be one object, what is the apparent magnitude of the combined object
Physics
1 answer:
lesya692 [45]3 years ago
7 0
Assuming that the magnitude is additive, then you simply have to add the brightness four times. This is because each star has 2 magnitudes of 8.34. As a result, you have to add 4 magnitudes of 8.34. The solution is as follows:

Magnitude = 4(8.34) 
Magnitude = 33.36
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If the velocity of a proton is straight up (thumb pointing up) then RHR2 shows that the force points to the left. What would the
diamong [38]

Answer:

a) to the right

b) up

c) down

d) there will be no force on the proton

e) there will be no force on the proton

Explanation:

The complete question is

If the velocity of a proton is straight up(thumb pointing up) then RHR2 (right hand rule) shows that the force points to the left. What would the direction of the force be if the velocity were a)down, b)to the right, c)to the left, d)into the page, and e)out of the page?

The right hand rule for a positive charge states that...

Hold the thumb of the right hand at right angle to the rest of the fingers, and the rest of the fingers parallel to one another, and pointing away from the body. If the thumb shows the velocity of a positive charge in a magnetic field, and the fingers all point in the direction of the magnetic field, then the palm will push in the direction of the force on the positive charge (proton).

From this, we can deduce from the original statement about this proton that the direction of the field is into the screen of this computer. with that field direction held constant, we can work out that

a) if the thumb point down, the force will be to the right

b) if the thumb points to the right, the force will be upwards

c)  if the thumb points to the left, the force is downwards

d)  if the thumb points into the page, then there will be no force on the proton since the proton must travel perpendicularly to the magnetic field for a force to be induced on it

e) explanation is the same as foe option d.

6 0
3 years ago
A car moves at the speed of 30km/h for 15 mins and then at the speed of 60km/h for the next 15 mins . how much dstance is covere
blagie [28]
Distance = speed x time. The total speed is 30 + 60 = 90km/h and the total time taken is 15 + 15 = 30 minutes. Therefore, you do 90 x 30 = 2700km

Answer = 2700km
6 0
2 years ago
What is the mass of a large ship that has a momentum of 1.60×109kg·m/s, when the ship is moving at a speed of 48.0 km/h? (b) Com
erastova [34]

a) The mass of the ship is 1.2\cdot 10^8 kg

b) The ship has a larger momentum than the shell

Explanation:

a)

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the ship in this problem, we have

p=1.60\cdot 10^9 kg m/s is the momentum

v=48.0 km/h \cdot \frac{1000 m/km}{3600 s/h}=13.3 m/s is the velocity

Solving for m, we find the mass of the ship:

m=\frac{p}{v}=\frac{1.60\cdot 10^9}{13.3}=1.2\cdot 10^8 kg

b)

The momentum of the artillery shell is given by

p=mv

where

m is its mass

v is its velocity

For the shell in this problem,

m = 1100 kg

v = 1200 m/s

Substituting,

p=(1100)(1200)=1.32\cdot 10^6 kg m/s

So, we see that the ship has a larger momentum.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

6 0
3 years ago
Posting on social media as a business can be a free way of generating interest in a childcare center's services.
max2010maxim [7]
We know this already
4 0
3 years ago
s) A body of mass 2 kilograms moves on a circle of radius 3 meters, making one revolution every 5 seconds. Find the magnitude of
jeyben [28]

Answer:

Centripetal force acting on the body = 9.47 N

Explanation:

Mass of body, m = 2 kg

Radius, r = 3 m

It makes one revolution in 5 seconds.

        Period, T = 5 s

        \texttt{Angular velocity, }\omega =\frac{2\pi }{T}=\frac{2\pi }{5}=1.256rad/s

Centripetal force, F = mrω²

                        F = 2 x 3 x 1.256² = 9.47 N

Centripetal force acting on the body = 9.47 N

8 0
3 years ago
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