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Kruka [31]
3 years ago
5

A double star has two components of equal brightness, each with a magnitude of 8.34. if these stars are so close together that t

hey appear to be one object, what is the apparent magnitude of the combined object
Physics
1 answer:
lesya692 [45]3 years ago
7 0
Assuming that the magnitude is additive, then you simply have to add the brightness four times. This is because each star has 2 magnitudes of 8.34. As a result, you have to add 4 magnitudes of 8.34. The solution is as follows:

Magnitude = 4(8.34) 
Magnitude = 33.36
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vector J is 3250m long in a 38.4 direction. Vector K is 1822 m long in a 58.8 direction. Find the magnitude and direction of the
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The resultant vector has a magnitude of 4998 m and a direction of 45.7°.

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The x component of the resultant vector is the sum of the x components of each individual vector.

x = 3250 cos 38.4 + 1822 cos 58.8

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Similarly, the y component of the resultant vector is the sum of the y components of each individual vector.

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