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3 years ago

What is row of the periodic table called

Chemistry

1 answer:

Anvisha [2.4K]3 years ago

7 0

Explanation:

row of the periodic table called periods

and group

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What mass of calcium hydroxide is formed when 10.0g of calcium oxide reacts with 10.0g of water?

nexus9112 [7]

The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with 10.0 g of water is 13.024 grams

calculation

from the equation

CaO + H2O → Ca(OH)2,

1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2

find the moles of each reactant

moles=mass/molar mass

moles of CaO= 10 g/56 g/mol=0.179 moles

moles of H2O = 10 g/18 g/mol 0.556 moles

CaO is the limiting reagent therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles

mass= moles x molar mass

= 0.176 moles x 74 g/mol = 13.024 grams

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4 years ago

According to the primordial soup model, which statement tells how the chemicals in Earth’s prehistoric surface came alive? A. Vo

Nikolay [14]

<span> A huge meteor struck the earth and caused the chemicals to change.</span>

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3 years ago

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Which of the following would you expect to have the highest value for entropy?

Anon25 [30]

Chemistry cool

<span>CO2 (g) is your answer</span>

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3 years ago

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Draw the structures of two stereoisomeric alkenes that would give 3-hexanol as the only major product of hydroboration

larisa [96]

Answer:

Cis- and trans-3-hexene are symmetric hydrocarons that give only one major product i.e 3-hexanol upon hydroboration.

Explanation:

During hydroboration of 3-hexene, borane (BH3) is added to the double bond of hexene, that transfers the hydrogen atoms to that carbon which becomes is bonded to the boron. The process of hydroboration is created in two steps that leads to the formation of 3-hexanol and boric acid. (please see figure)

Now, the two stereoisomers, Cis- and trans-3-hexene both will give off the 3-hexanol upon hydroboration and the structure of these are illustrated in the figure.

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3 years ago

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Determine the percent yield for the reaction

kkurt [141]

Answer:

The percent yield for Br₂ in the reaction = 96.15%

Explanation:

The balanced stoichiometric equation for the reaction is given as

2 NaBr + 1 Cl₂ → 2 NaCl + 1 Br₂

Percent yield

= 100% × (Actual yield)/(Theoretical yield)

To find the theoretical yield,

5.29 g of NaBr reacts with excess chlorine

gas; this means that NaBr is the limiting reagent because it is used up in the process of the reaction, hence, it determines the amount of products to be found.

So, we convert the 5.29 g of NaBr into number of moles.

Number of moles = (Mass)/(Molar mass)

Molar Mass of NaBr = 102.894 g/mol

Number of moles = (5.29/102.894) = 0.0514121329 = 0.05141 mole

From the stoichiometric balance of the reaction,

2 moles of NaBr give 1 mole of Br₂

0.05141 mole of NaBr will give (0.05141×1/2) mole of Br₂; that is, 0.0257 mole of Br₂

Theoretical yield = Mass of Br₂ expected from the reaction

= (Number of moles) × (Molar mass)

Molar mass of Br₂ = 159.808 g/mol

Theoretical yield of Br₂ = 0.0257 × 159.808 = 4.108 g

Percent yield

= 100% × (Actual yield)/(Theoretical yield)

Actual yield = 3.95 g

Theoretical yield = 4.108 g

Percent yield = 100% × (3.95/4.108) = 96.15%

Hope this Helps!!!

5 0

4 years ago