Answer:
5
Explanation:
all you do is the math expression
Answer:
New temperature T2 = -124.7 °C
Explanation:
Given:
Old volume V1 = 135 cm³
New volume V2 = 140 cm³3
Old temperature T1 = 143 K
Find:
New temperature T2
Computation:
V1 / T1 = V2 / T2
135 / 143 = 140 / T2
New temperature T2 = 148.3 K
New temperature T2 = 148.3 - 273
New temperature T2 = -124.7 °C
A cube has a volume of 8.0 cm3 and a mass of 21.6 grams. ... using an electronic analytical balance. ... graduated cylinder ... The density of iron is 7.87 g/mL.